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(5 x 10000000000) + (2 x 1000000000) + (0 x 100000000) + (0 x 10000000) + (0 x 1000000) + (0 x 100000) + (0 x 10000) + (0 x 1000) + (0 x 100) + (0 x 10) + (0 x 1)
it is 0 because 6 x 0 =0 then 0 x 5 =0
(4 x 100000000) + (8 x 10000000) + (0 x 1000000) + (3 x 100000) + (0 x 10000) + (0 x 1000) + (5 x 100) + (4 x 10) + (0 x 1).
x2 - 2x - 10 = 5 x2 - 2x - 15 = 0 (x - 5)(x + 3) = 0 x - 5 = 0 and x + 3 = 0 So, x = 5 and x = -3
Yes, this can be done this way:(x-(-5))(x+a)=0, where a is any (positive or negative) numberThis simplifies to: (x+5)(x+a) = 0or written as quadratic: x2+(a+5)x+5a = 0Solutions: x1 = -5 and x2 = -a,so if a=5 the equation shortens to (x+5)2=0 ( or x2+10x+25=0 )and there will be only one solution: x1,2 = -5