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To find the x-intercept, plug 0 in for y:

0 = -x-1, so x = -1.

To find the y-intercept, plug zero in for x:

y=-0-1, so y = -1

The x-intercept is (0,-1) and the y-intercept is (-1,0)

Q: What is the x-intercept and y-intercept of the equation y equals -x-1?

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It is linear. The highest power is 1 (x = x1, y = y1) so it is linear.

i think its pretty much the same thing because matrix X1 X2 IS ACTUALLY X1 X2

(y-y1)=(y2-y1/x2-x1)(x-x1)

The equation for the slope between the points A = (x1, y1) and B = (x2, y2) = (y2 - y1)/(x2 - x1), provided x1 is different from x2. If x1 and x2 are the same then the slope is not defined.

Approach by 2 formulas; slope m= (y2-y1)/(x2-x1) and the equation of the line is (y-y1)= m*(x-x1) where point 1 is (x1,y1) and point 2 is (x2,y2)

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It shows the relationship of y in terms of x. [y = (yIntercept) + ((slope)*(x))] [slope = (y2 - y1)/(x2 - x1)]

it equals x1 it equals x1

use the formula y-y1=m(x-x1)

It is linear. The highest power is 1 (x = x1, y = y1) so it is linear.

3

i think its pretty much the same thing because matrix X1 X2 IS ACTUALLY X1 X2

if sqrt(x) + 8 = 0, then: x1/2+8 = 0 x1/2 = -8 (x1/2)2 = (-8)2 x = 64 √x + 8 = 0 is a contradiction equation, because the equivalent equation √x = -8 is not a true statement, because √x = |x| = positive. So that, - √x + 8 = 0 is true for x = 64.

(y-y1)=(y2-y1/x2-x1)(x-x1)

The equation for the slope between the points A = (x1, y1) and B = (x2, y2) = (y2 - y1)/(x2 - x1), provided x1 is different from x2. If x1 and x2 are the same then the slope is not defined.

Approach by 2 formulas; slope m= (y2-y1)/(x2-x1) and the equation of the line is (y-y1)= m*(x-x1) where point 1 is (x1,y1) and point 2 is (x2,y2)

(y-y1)=m(x-x1) OR we can write it y=m(x-x1)+y1

(y - y1) = m*(x - x1) where (x1, y1) are the coordinates of a point on the line and , is the slope.