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Is the equation x plus y equals 4 linear or not?
It is linear. The highest power is 1 (x = x1, y = y1) so it is linear.
How matrix X1 X2 equals matrix X1 X2?
i think its pretty much the same thing because matrix X1 X2 IS ACTUALLY X1 X2
How to get the equation of a line that passes through these two points?
(y-y1)=(y2-y1/x2-x1)(x-x1)
How do you do equations and graphs for slope?
The equation for the slope between the points A = (x1, y1) and B = (x2, y2) = (y2 - y1)/(x2 - x1), provided x1 is different from x2. If x1 and x2 are the same then the slope is not defined.
How do you find an equation of a line through two points?
Approach by 2 formulas; slope m= (y2-y1)/(x2-x1) and the equation of the line is (y-y1)= m*(x-x1) where point 1 is (x1,y1) and point 2 is (x2,y2)
What is a slope used for?
It shows the relationship of y in terms of x. [y = (yIntercept) + ((slope)*(x))] [slope = (y2 - y1)/(x2 - x1)]
X plus one over x squared plus two?
it equals x1 it equals x1
Determine if the point 3-4 is a solution for the equation y equals 8 -4x?
use the formula y-y1=m(x-x1)
Is the equation x plus y equals 4 linear or not?
It is linear. The highest power is 1 (x = x1, y = y1) so it is linear.
Maxz equals 2x1 plus 2x2 stc 5x1 plus 3x2 equals 8 x1 plus 2x2 equals 4 x1 x2 equals 0 and integerssolve by ipp?
3
How matrix X1 X2 equals matrix X1 X2?
i think its pretty much the same thing because matrix X1 X2 IS ACTUALLY X1 X2
How to get the equation of a line that passes through these two points?
(y-y1)=(y2-y1/x2-x1)(x-x1)
What is the square root of x plus 8 equals 0?
if sqrt(x) + 8 = 0, then: x1/2+8 = 0 x1/2 = -8 (x1/2)2 = (-8)2 x = 64 √x + 8 = 0 is a contradiction equation, because the equivalent equation √x = -8 is not a true statement, because √x = |x| = positive. So that, - √x + 8 = 0 is true for x = 64.
How do you do equations and graphs for slope?
The equation for the slope between the points A = (x1, y1) and B = (x2, y2) = (y2 - y1)/(x2 - x1), provided x1 is different from x2. If x1 and x2 are the same then the slope is not defined.
How do you find an equation of a line through two points?
Approach by 2 formulas; slope m= (y2-y1)/(x2-x1) and the equation of the line is (y-y1)= m*(x-x1) where point 1 is (x1,y1) and point 2 is (x2,y2)
What is a point slope form equation?
(y-y1)=m(x-x1) OR we can write it y=m(x-x1)+y1
What is a point slope equation of a line?
(y - y1) = m*(x - x1) where (x1, y1) are the coordinates of a point on the line and , is the slope.
