(y-y1)=m(x-x1) OR we can write it y=m(x-x1)+y1
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Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
You use point-slope form to find the equation of a line if you only have a point and a slope or if you are just given two point. Usually you will convert point-slope form to slope-intercept form to make it easier to use.
If you know the slope of the line that your equation is perpendicular too, you find the negative reciprocal of it and use it as the slope for the line. (negative reciprocal = flip the slope over and change its sign. Ex: a slope of 2 has a negative reciprocal of -1/2. ) Then you use the given point, and put your equation in point-slope form. The general equation for point slope form is Y-y1=m(x-x1) The y1 is the y coordinate of the given point. X1 is the x coordinate of the given point. M is the slope that you found earlier. You now have your equation. If you are asked to put it in slope intercept form, simply distribute the numbers and solve the equation for y.
Point: (2, 4) Slope: -3 Equation: y = -3x+10
Slope intercept form is y = mx + b. Point slope form is y - y1 = m(x - x1). Here is an example of changing slope-intercept form to point-slope form: Change y = 3x + 2 to point slope form: y = 3x + 2 Subtract 2 from each side: y -2 = 3x The equation y-2 = 3x is in point-slope form. It can be rewritten as y-2 = 3(x-0), showing that the line passes through the point (0,2), but is doesn't need to be. (The x1 and y1 represent one point on the line, it doesn't matter which one. Therefore, there are many different equations for the same line in point-slope form. For example, the equation y -2 = 3x is the same line as the equation y - 11 = 3(x - 3), which is the same line as the equation y + 4 = 3(x + 2).)