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8
4
x + y = 6 2x + y = 8 Subtract the top equation from the bottom one: 2x - x + y - y = 8 - 6 x = 2 Going to the top equation, substituting 2 for x: 2 + y = 6 Which you should be able to solve if you are asking this question.
The output or y-value when you input x-4 into the function y = 2x + 6 is 2(x-4) + 6 = 2x - 8 + 6 = 2x - 2.
[y-(-8)]/[x-(-1)] = 6 y + 8 = 6 (x + 1) y = 6x -2
8
4
x + y = 6 2x + y = 8 Subtract the top equation from the bottom one: 2x - x + y - y = 8 - 6 x = 2 Going to the top equation, substituting 2 for x: 2 + y = 6 Which you should be able to solve if you are asking this question.
The output or y-value when you input x-4 into the function y = 2x + 6 is 2(x-4) + 6 = 2x - 8 + 6 = 2x - 2.
y=2x+8 x+y=-1 From the second you get x = -1-y, put in the first y=2*(-1-y)+8 then y = -2 y +6 3y = 6 => y = 2 and x = -3
-6
2x + 4 = y ...............2x + 4 = y ....................2x + 4 = y .............2*(-6)+ 4 = y x - y = 2 .......<=> ...x - 2x - 4 = 2 .....<=> ...x = -6......... <=>.... x = -6 ..............<=> y = - 8 x = - 6
-6
y is 2/3.
If you mean: y = x-2 and y = 2x-8 then it works out that x = 6 and y = 4
-2 and -4. The factor pairs of 8 are: {2, 4}, {1, 8}, {-1, -8}, {-2, -4} The sum of the pairs are 6, 9, -9, -6; Thus the required pair is {-2, -4}.
y - 8 = x^2 + 12x + 36 y - 8 = (x + 6)^2 y = (x + 6)^2 + 8 or f(x) = (x + 6)^2 + 8 So -h = 6 so that h = -6, and k = 8