What is the x intercepts and the y intercepts of f of x of the equation f of x equals x2 minus 5x plus 2?

Answer 1

F(x)=x**2-5*x+2

y-int (where x=0):

0**2-5*0+2 = 2

(0,2)

x-int (where y=0):

0=x**2-5x+2

use quadratic equation

(-(-5)+sqrt((-5)**2-4*1*-5))/2 = 0.5*(5+sqrt(17))

(-(-5)-sqrt((-5)**2-4*1*-5))/2 = 0.5*(5-sqrt(17))

(0.5*(5+sqrt(17)),0),

(0.5*(5-sqrt(17)),0)

Answer 2

The x-intercepts are the points where the graph of the equation intersects the x-axis. To find them, set f(x)=0 and solve for x. For the equation f(x)=x^2-5x+2, you can use factoring or the quadratic formula to find the x-intercepts.

The y-intercept is the point where the graph intersects the y-axis. To find it, substitute x = 0 into the equation f(x)=x^2-5x+2 and solve for f(x).