x2 of 2 = 2x2
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the square root of 1936 is 2 x 2 x 2 x 2 x 11 x11 Therefore : 2 x 2 x11 = 44 (answer)
x2 - 6x + 1 = 0 x = [-(-6) +&- square root of [(-6)2 - 4(1)(1)]]/2(1) x = (6 +&- square root of 32)/2 x = [6 +&- 4(square root of 2)]/2 x = 3 +&- 2(square root of 2) x = 3 + 2(square root of 2) or x = 3 - 2(square root of 2) Check:
Its the square root of 2 times x Ambiguous. More clear is x times square root of 2
Complete the square. X^2 + 2X halve the linear term ( 2 ), square it and add to polynomial X^2 + 2X + 1
y = x^(1/2) (NB power of '1/2' mean the 'square root'. Hence dy/dx = (1/2)x^(-1/2) or dy/dx = 1/ [2x^(1/2)]