y intercept is value of y when x = 0 x intercept is value of x when y = 0 if y intercept is twice x intercept then its value is twice as high Mathematically, the standard form equation is y = mx + b where m = slope and b = y intercept for x intercept let y = 0 0 = mx + b x = -b/m = 1/2 y intercept = 1/2 time b m = -2 y = -2x + b is the equation
If that should be y = 2 the slope is 0 and the y intercept is 2.
1. Write the equation in y=mx+b. 2. b is the y-intercept. Ex. 1. y=9x+0 2. b=0. The y-intercept of y=9x is 0. Hint: Since this is a direct variation problem (y=kx), the x-intercept is also 0.
2
if:y = -2x + 3then:if y = 0:0 = -2x + 32x = 3x = 3/2if x = 0:y = -2(0) + 3y = 3So the x-intercept is at {0, 3}, and the y-intercept is at {3/2, 0}
x-intercept: 1. substitute 0 for y 2. solve for x y-intercept: 1. substitute 0 for x 2. solve for y
y intercept is value of y when x = 0 x intercept is value of x when y = 0 if y intercept is twice x intercept then its value is twice as high Mathematically, the standard form equation is y = mx + b where m = slope and b = y intercept for x intercept let y = 0 0 = mx + b x = -b/m = 1/2 y intercept = 1/2 time b m = -2 y = -2x + b is the equation
If that should be y = 2 the slope is 0 and the y intercept is 2.
When finding the y-intercept, plug in x=0 y = 4x + 2 y = 4(0) + 2 y = 2 So your intercept is (0,2)
It is in slope intercept form. The slope is 0 and the y-intercept is -2.
1. Write the equation in y=mx+b. 2. b is the y-intercept. Ex. 1. y=9x+0 2. b=0. The y-intercept of y=9x is 0. Hint: Since this is a direct variation problem (y=kx), the x-intercept is also 0.
2
If you mean a slope of 4 and points of (0, 2) then the equation is y = 4x+2.
x-intercept: (2/3, 0) y-intercept: (0, 2)
Ah, let's paint a happy little picture with this equation. To find the x-intercept, we set y to 0 and solve for x. So, -10x = -20, which gives us x = 2. For the y-intercept, we set x to 0 and solve for y. So, -10y = -20, which gives us y = 2. And just like that, we've found our x-intercept at (2, 0) and y-intercept at (0, 2).
If: x-y = -2 then the x intercept is -2 and the y intercept is 2 So the points are: (-2, 0) and (0, 2)
If you mean x intercept -2 and y intercept -1 then the points are (-2, 0 and (0,-1) Slope: -1/2 Equation: y - -1 = -1/2(x -0) => 2y --2 = -x +0 => 2y = -x -2 Equation in slope intercept form: y = -1/2x -1