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What is the equation of a line in slope-intercept form for a line with slope 4 and y-intercept at 0 2?
Wiki User
∙ 8y ago
If you mean a slope of 4 and points of (0, 2) then the equation is y = 4x+2.
Wiki User
∙ 8y ago
Marion Mosley
Slope: 0 y-intercept: 9
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Write the equation in slopeintercept form of the line that has a slope of 3 and contains the point 4 9?
The equation of the line is of the form y = 3x + c where c is a constant. The point (4,9) is on the line, so substituting x=4, y=9 in the equation, 9 = 3*4 + c = 12 + c so c = -3 So the equation of the line is y = 3x - 3
What is an equation of the line that passes through the point 50 and is perpendicular to the line 5x 6y24 express your answer in slope-intercept form?
Here is how to solve it. First, find the slope of the given line. To do this, solve the equation for "y". That will convert the equation to the slope-intercept form. From there, you can immediately read off the slope. Since parallel lines have the same slope, the line you are looking for will have the same slope. Now you need to use the point-slope form of the equation, with the given point, and the slope you just calculated. Finally, solve this equation for "y" to bring it into the requested slope-intercept form.
How do you convert an equation in standard form to slope-intercept form?
Solve the equation for ' y '.
Write the equation in slope intercept form of the line that has a slope of 2 and Y intercept of 2?
The slope-intercept form of an equation is: y = mx + b Just copy down this equation, then replace "m" with the slope, and "b" with the y-intercept.
Where is the slope in an equation?
Before you can spot the slope, you absolutely must massage the equation so thatit's in the right form. The right form isy = Ax + B . . . and ' A ' and ' B ' are just numbers.When your equation is in that form, then ' A ' is the slope of the graph, and ' B ' is the y-intercept.
Write the equation in slopeintercept form of the line that has a slope of 2 and contains the point 3 7?
y = 2x + 1.
How do you write an equation of a line that passes through the xintercep and yintercept?
You can write it either in standard form (ax + by = c) or in slope-intercept form (y = mx + b)
Write the equation in slopeintercept form of the line that has a slope of 3 and contains the point 2 5?
y=mx+b y0=mx0+b 5=3*2+b b=5-5=0 y=3x+0
Write the equation in slopeintercept form of the line that has a slope of 3 and contains the point 4 9?
The equation of the line is of the form y = 3x + c where c is a constant. The point (4,9) is on the line, so substituting x=4, y=9 in the equation, 9 = 3*4 + c = 12 + c so c = -3 So the equation of the line is y = 3x - 3
What is the slope intercept form of this equation?
The slope-intercept form of an equation is y = mx + b, where m is the slope and b is the y-intercept. Without the specific equation, it is not possible to determine the values of m and b for the slope-intercept form.
How do you turn standard equations in slope intercept equations?
slopeintercept equations are used to find the slope and intercept (obviously lol) they are set up like this y=mx+b m is the slope and b is the y-intercept lets say you have an equation like... 2x + y = 5 (now minus 2x from both sides) 2x - 2x + y = 5 - 2x (simplify) y = 5 - 2x just use algebra to turn the standard form to slope intercept form
Slope-intercept form of an equation is?
Slope-intercept form is easy! The equation is y=mx+b (X)(X) O______O
When does the equation of a line in slope-intercept form look just like its equation in point-slope form?
When it is a line through the origin.
How do you identify a slope given in a linear equation?
To identify the slope in a linear equation, rearrange the equation into the form y = mx + b. The term m is the slope.
What part of the general slope intercept equation represents the slope?
The general form of the slope-intercept equation is y = mx + b. In that equation, the slope is m and the y intercept is b.
What is an equation of the line that passes through the point 50 and is perpendicular to the line 5x 6y24 express your answer in slope-intercept form?
Here is how to solve it. First, find the slope of the given line. To do this, solve the equation for "y". That will convert the equation to the slope-intercept form. From there, you can immediately read off the slope. Since parallel lines have the same slope, the line you are looking for will have the same slope. Now you need to use the point-slope form of the equation, with the given point, and the slope you just calculated. Finally, solve this equation for "y" to bring it into the requested slope-intercept form.
How do you write an equation in slope inercept form if there is no slope?
you say undefined
