8x+4y=20 4y=-8x+20 y=-2x+5 f(x)=-2x+5
I presume that since you labeled this as a Calculus problem that you mean x * 4y = 12? x * 4y = 12 ---> 4y = 12 / x ---> y = 3 / x ---> y = 3 * x^(-1) You will notice that this function is not a line, but a curve. The slope will be different at different points on the line. Thus, we can't find the slope of the entire function, but we CAN find a function which gives us the slope of a tangent line at any point on the function. We do this by taking the derivative. For f(x) = a * x^(n) f'(x) = a * n * x^(n-1) Using a = 3 and n = -1, we have: y = f(x) = 3 * x^(-1) dy/dx = f'(x) = 3 * -1 * x^(-1 - 1) = -3 * x^(-2) So your answer will be: dy/dx = -3 * x^(-2)
All of them
it equals 1
Feet in a Furlong
8x+4y=20 4y=-8x+20 y=-2x+5 f(x)=-2x+5
I presume that since you labeled this as a Calculus problem that you mean x * 4y = 12? x * 4y = 12 ---> 4y = 12 / x ---> y = 3 / x ---> y = 3 * x^(-1) You will notice that this function is not a line, but a curve. The slope will be different at different points on the line. Thus, we can't find the slope of the entire function, but we CAN find a function which gives us the slope of a tangent line at any point on the function. We do this by taking the derivative. For f(x) = a * x^(n) f'(x) = a * n * x^(n-1) Using a = 3 and n = -1, we have: y = f(x) = 3 * x^(-1) dy/dx = f'(x) = 3 * -1 * x^(-1 - 1) = -3 * x^(-2) So your answer will be: dy/dx = -3 * x^(-2)
All of them
it equals 1
26
f = 54
x = 75
-8
300 Celsius equals 572 degrees F
-2
Feet in a Furlong
F = MA M = F / A A = F / M