2y = -3x - 10
∴ y = -3x/2 - 5
Let Y equal zero, then:
0 = -3x/2 - 5
∴ 3x/2 = -5
∴ 3x = -10
∴ x = -10/3
So the y-intercept occurs at the point (-10/3, 0)
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This means that 2y - 3 = 2y + 4 which is not possible.
2y=8..... y=4
2y+26 = 28 2y = 28-26 2y = 2 y = 1
x = 11 - 2y and 14 - 2y. This means that 11 = 14. Is there a typo in the question?
For y - 2y - 3y equals 0, y equals 0.
This means that 2y - 3 = 2y + 4 which is not possible.
If 3y = 12, 2y = 8
2y=8..... y=4
2y+26 = 28 2y = 28-26 2y = 2 y = 1
-11/6
x = 11 - 2y and 14 - 2y. This means that 11 = 14. Is there a typo in the question?
(3, 2)
For y - 2y - 3y equals 0, y equals 0.
-2y = 10 2y = -10 y = -5
2y= 32 y=16
-2y=x+8 is the answer
2y(x+2)=