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What is the slope of the line that has the equation 4x plus 2y equals 12?

what is the slope of the line that has the equation 4x+2y=12?


What is 3x plus 2y equals 8?

3x + 2y = 8 This is an equation. It could be the equation of a line.


What is the y-intercept of the line with the equation 4x plus 2y equals 12?

(0,6)


What is -x plus 2y equals 12?

It is a straight line equation that can be rearranged into slope intercept form: -x+2y = 12 2y = x+12 y = 0.5x+6 which is now in slope intercept form


What is the effect on the graph of the equation 4x plus 2y equals 12 if 12 is changed to 36?

Changing the equation from (4x + 2y = 12) to (4x + 2y = 36) will affect the position of the line on the graph. Specifically, the new equation represents a line that is parallel to the original line but shifted upwards. This is because both equations have the same slope, but the y-intercept changes, resulting in a higher intercept on the y-axis for the new equation. Thus, the line will intersect the y-axis at (y = 18) instead of (y = 6).


What is the slope of the line whose equation is -2y equals 5x-12?

The slope (m) is -2.5 -2y = 5x-12 -2y/-2 = (5x-12)/-2 y=-2.5x + 6 or more neatly: y= 6-2.5x


Which equation represents a line that is parallel to the line whose equation is 2x 3y12?

2y= 3x+6


Solve for y if the equation is -2x - 2y equals -12?

-2x - 2y = -122x + 2y = 122y = 12 - 2xy = 6 - x


What is the point of contact between the tangent line x -2y plus 12 equals 0 and the circle x2 plus y2 -x -31 equals 0?

It works out that the tangent line x -2y +12 = 0 makes contact with the circle x^2 +y^2 -x -31 = 0 at the point (-2, 5) ------------------------------------------------- The equation of the tangent line can be rearranged to isolate x: x - 2y + 12 = 0 → x = 2y - 12 This can now be substituted for x in the equation of the circle and solved to find the value(s) of y: x² + y² - x - 31 = 0 → (2y - 12)² + y² - (2y - 12) - 31 = 0 → 4y² - 48y + 144 + y² - 2y + 12 - 31 = 0 → 5y² - 50y - 125 = 0 → y² - 10y - 25 = 0 → (y - 5)² = 0 This is a repeated root showing a single point of contact, so the line IS a tangent to the circle. → y - 5 = 0 → y = 5 Substitute into the equation for the line: → x = 2y - 12 = 2×5 - 12 = 10 - 12 = -2 → point of contact is (-2, 5)


What are the points of intersection of the straight line x -2y equals 8 with the curve of xy equals 24?

We solved the first equation for 'x': [ x = 2y + 8 ].Then we substituted it for 'x' in the second equation and rearranged: [ y2 + 4y - 12 = 0 ].Solutions of this quadratic equation are: y = 2 and -6. From which x = 12 and -4 .So the straight line intersects the hyperbola at (-4, -6) and at (12, 2) .


How do you solve this equation 3x plus 2y equals 12 solve for y?

3x + 2y = 12 ie 2y = 12 - 3x so y = 6 - 3x/2


What is the slope of the line that has the equation 4x 2y 12?

Impossible to say because the equal, the positive and/or the negative signs or instructions are missing in your question.