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What is the slope of a line with the equation y12x?
If the equation is y=12x, the slope is 12
If y12x - 2 were changed to y12x how would the graph of the new function compare with the original?
If you mean y = 12x -2 and y = 12x then both slopes will be parallel but with the changed function having its slope passing through the origin (0, 0)
What is the slope of the line given by the equation y12x-23?
35
Which situation can be represented by y12x-4?
If you mean: y = 12x-4 then it is a straight line equation that can be plotted on the Cartesian plane.
If y12x-2 were changed to y12x how would the graph of the new function compare to the original?
The graph would be translated upwards by 2 units.
What is the slope of a line with the equation y12x?
If the equation is y=12x, the slope is 12
What is the slope of the line with equation y12x?
If you mean y = 12x then the slope of the line is 12
If y12x - 2 were changed to y12x how would the graph of the new function compare with the original?
If you mean y = 12x -2 and y = 12x then both slopes will be parallel but with the changed function having its slope passing through the origin (0, 0)
Does y12x 1 have a negative or positive slope?
If you mean: y = 12x+1 then it has a positive slope of 12 and a y intercept of 1
Which situation can be represented by y12x-4?
If you mean: y = 12x-4 then it is a straight line equation that can be plotted on the Cartesian plane.
What is the slope of the line given by the equation y12x-23?
35
What is the answer for x0 for the function y12x plus 88?
If x is zero, then y12x is also zero. The answer is therefore 88.
Is the point 69 a solution of the equation y12x 6?
If this question is asking: is the point (6,9) a solution of the equation y = 12x + 6, then NO, it's not a solution.
How do you get to fremnnik isles one runescape?
teleport to camelot and follow the path that leads west to the first interscetion then go norththen at the next interscetion go west then follow that path to fremnik isles
If y12x-2 were changed to y12x how would the graph of the new function compare to the original?
The graph would be translated upwards by 2 units.
What is the domain of y12x?
The expression ( y = 12x ) is a linear equation in two variables, ( x ) and ( y ). The domain of ( y ) is the set of all possible values for ( x ), which is all real numbers, denoted as ( (-\infty, \infty) ). Thus, for any real number ( x ), there is a corresponding value of ( y ).
Does this slope has a positive or negative slope y12x 1?
The expression "y12x 1" seems to be a typographical error or unclear representation of a mathematical equation. If you meant to write a linear equation in the form of (y = mx + b), where (m) represents the slope, please clarify the equation. However, if the slope coefficient (m) is positive, the slope is positive; if it is negative, the slope is negative.
