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What is this expression as an algebraic expression cos parenthesis arccosx-arcsinx parenthesis?
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∙ 10y ago
The above expression cannot be expressed in an algebraic form.
Wiki User
∙ 10y ago
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How do you solve cos theta subtract cos squared theta divide 1 plus cos theta?
The question contains an expression but not an equation. An expression cannot be solved.
How to solve sin of cos inverse of x?
sin[cos-1(x)] is an expression; it is not an equation (nor inequality). An expression cannot be solved.
How do you solve sin parenthesis cos to the negative 1 parenthesis 2 over 5 closed parenthesis and another closed parenthesis?
Let y = sin(cos-1(2/5)) Suppose x = cos-1(2/5): that is, cos(x) = 2/5 then sin2(x) = 1 - cos2(x) = 1 - 4/25 = 21/25 so that sin(x) = sqrt(21)/5 which gives x = sin-1[sqrt(21)/5] Then y = sin(cos-1(2/5)) = sin(x) : since x = cos-1(2/5) =sin{sin-1[sqrt(21)/5]} = sqrt(21)/5 There will be other solutions that are cyclically related to this one but no range has been given for the solutions.
How do you find T8 sec x cos x?
If cos(x) = 0 then the expression is undefined. Otherwise, it is T8.
What is sin23A minus sin7A upon sin2A plus sin14A if A equals pi upon 21?
Using the identity, sin(X)+sin(Y) = 2*sin[(x+y)/2]*cos[(x-y)/2] the expression becomes {2*sin[(23A-7A)/2]*cos[(23A+7A)/2]}/{2*sin[(2A+14A)/2]*cos[(2A-14A)/2]} = {2*sin(8A)*cos(15A)}/{2*sin(8A)*cos(-6A)} = cos(15A)/cos(-6A)} = cos(15A)/cos(6A)} since cos(-x) = cos(x) When A = pi/21, 15A = 15*pi/21 and 6A = 6*pi/21 = pi - 15pi/21 Therefore, cos(6A) = - cos(15A) and hence the expression = -1.
Why can't we use capital letters in an algebraic expression?
This is a ridiculous question because you can use capital letters. By The Dark Overlord.
How will you relate rational algebraic expression to golden traigle or golden ratio?
There are a couple: (1+SQRT(5))/2 1/(2*cos(72)) (degrees only)
How do you solve cos theta subtract cos squared theta divide 1 plus cos theta?
The question contains an expression but not an equation. An expression cannot be solved.
How to solve sin of cos inverse of x?
sin[cos-1(x)] is an expression; it is not an equation (nor inequality). An expression cannot be solved.
How do you solve sin parenthesis cos to the negative 1 parenthesis 2 over 5 closed parenthesis and another closed parenthesis?
Let y = sin(cos-1(2/5)) Suppose x = cos-1(2/5): that is, cos(x) = 2/5 then sin2(x) = 1 - cos2(x) = 1 - 4/25 = 21/25 so that sin(x) = sqrt(21)/5 which gives x = sin-1[sqrt(21)/5] Then y = sin(cos-1(2/5)) = sin(x) : since x = cos-1(2/5) =sin{sin-1[sqrt(21)/5]} = sqrt(21)/5 There will be other solutions that are cyclically related to this one but no range has been given for the solutions.
How do you simplify tan theta cos theta?
Remember that tan = sin/cos. So your expression is sin/cos times cos. That's sin(theta).
How do you find T8 sec x cos x?
If cos(x) = 0 then the expression is undefined. Otherwise, it is T8.
What is this expression as the cosine of an angle cos30cos55 plus sin30sin55?
cos(30)cos(55)+sin(30)sin(55)=cos(30-55) = cos(-25)=cos(25) Note: cos(a)=cos(-a) for any angle 'a'. cos(a)cos(b)+sin(a)sin(b)=cos(a-b) for any 'a' and 'b'.
Cos series expression?
cos(x) = 1 - x2/2! + x4/4! - x6/6! + ... where x is the angle measured in radians.
What is cos theta minus cos theta times sin squared theta?
cos(t) - cos(t)*sin2(t) = cos(t)*[1 - sin2(t)] But [1 - sin2(t)] = cos2(t) So, the expression = cos(t)*cos2(t) = cos3(t)
The expression sec x - sin x tan x is equivalent to?
cos x
What is sin23A minus sin7A upon sin2A plus sin14A if A equals pi upon 21?
Using the identity, sin(X)+sin(Y) = 2*sin[(x+y)/2]*cos[(x-y)/2] the expression becomes {2*sin[(23A-7A)/2]*cos[(23A+7A)/2]}/{2*sin[(2A+14A)/2]*cos[(2A-14A)/2]} = {2*sin(8A)*cos(15A)}/{2*sin(8A)*cos(-6A)} = cos(15A)/cos(-6A)} = cos(15A)/cos(6A)} since cos(-x) = cos(x) When A = pi/21, 15A = 15*pi/21 and 6A = 6*pi/21 = pi - 15pi/21 Therefore, cos(6A) = - cos(15A) and hence the expression = -1.
