No. Cos squared x is not the same as cos x squared. Cos squared x means cos (x) times cos (x) Cos x squared means cos (x squared)
It is cotangent(theta).
cosec(q)*cot(q)*cos(q) = 1/sin(q)*cot(q)*cos(q) = cot2(q)
zero
It is cos2x that is, "cos-squared x".
Tan^2
Cos theta squared
- cos theta
Zero. Anything minus itself is zero.
You can use the Pythagorean identity to solve this:(sin theta) squared + (cos theta) squared = 1.
cosine (90- theta) = sine (theta)
1
cos2(theta) = 1 so cos(theta) = ±1 cos(theta) = -1 => theta = pi cos(theta) = 1 => theta = 0
The question contains an expression but not an equation. An expression cannot be solved.
Until an "equals" sign shows up somewhere in the expression, there's nothing to prove.
COS squared Theta + SIN squared Theta = 1; where Theta is the angles measurement in degrees.
Remember that tan = sin/cos. So your expression is sin/cos times cos. That's sin(theta).