45+54=99
99*2=198
198 is the answer.
To find 54 more than the sum of 12 and 33, first calculate the sum of 12 and 33, which is 45. Then, add 54 to this sum: 45 + 54 equals 99. Therefore, 54 more than the sum of 12 and 33 is 99.
Possibility of two digit no whose sum is 9 18,27,36,45,54,63,72,81 Subract 9 with each no mentioned above output is 9,18,27,36,45,54,63,72 See after 4th comma 54 and 45. Reverse 54=45. now 45 is 9 less than 54. So the original no is 54
(18 + 36) + (45 - 27) = 54 + 18 = 72
45, 60, and 75
45
The numbers between 40 and 60 that are divisible by 9 are 45 and 54. 45/9=5 and 54/9=6. The sum of 45 and 54 is 99.
Possibility of two digit no whose sum is 9 18,27,36,45,54,63,72,81 Now add 9 to each no mentioned above 27,36,45,54,63,72,81,90 See after 3rd comma 45 and 54. reverse of 45 is 54. 54 is 9 more than 45. So 45 is the original
Possibility of two digit no whose sum is 9 18,27,36,45,54,63,72,81 Subract 9 with each no mentioned above output is 9,18,27,36,45,54,63,72 See after 4th comma 54 and 45. Reverse 54=45. now 45 is 9 less than 54. So the original no is 54
(18 + 36) + (45 - 27) = 54 + 18 = 72
45, 60, and 75
45
Possibility of two digit no whose sum is 9 18,27,36,45,54,63,72,81 Now add 9 to each no mentioned above 27,36,45,54,63,72,81,90 See after third comma 45 and 54. Reverse of 45 is 54. 54 is 9 more than the no 45. So 45 is original
45, 60, and 75
45 + 54 = 99
This has several values.The perimeter is twice the sum of any two numbers whose product is 54.
54.
Possibility of two digit no whose sum is 9 18,27,36,45,54,63,72,91 Now add 9 to each no mentioned above 27,36,45,54,63,72,91,100 See after third comma 45 and 54. If you reverse 45 it will be 54. which is 9 more than 45. So original no is 45