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Find three consecutive even integers such that the sum of the first twice the second and three times the third is 124?
18, 20 and 22
How Find three consecutive even integers such that three times the first integer i six more than twice the second integer?
They are 14, 16 and 18.
The sum of three consecutive multiples of 8 is 888 find the multiple?
The numbers must total 888/8 ie 111. The middle number is 1/3 of 111 ie 37 so the three numbers are 36, 37 and 38 and multiples are 288, 296 and 304.
Find three consecutive odd integers such that the sum of the first integer twice the second integer and three times the third is 70?
9, 11, and 139 + 2(11) + 3(13) = 9 + 22 + 39 = 70
Find two consecutive integers such that the larger is nine more than twice the smaller?
-10 and -11.
If sum of three consecutive multiples of 7 is equal to 252 Find the highest number?
91
Find three consecutive even integers such that the sum of the first twice the second and three times the third is 124?
18, 20 and 22
The sum three consecutive multiples of 6 is 666 find these multiples?
Let the second of the three consecutive multiples of 6 be 6n Then the first is 6n - 6 and the last is 6n + 6; and: (6n - 6) + 6n + (6n + 6) = 666 → 18n = 666 → n = 37 → the consecutive multiples of 6 which sum to 666 are 216, 222, 228
How Find three consecutive even integers such that three times the first integer i six more than twice the second integer?
They are 14, 16 and 18.
How Find three consecutive even integers such that three times the first integer is six more than twice the second integer?
The numbers are 14, 16 and 18.
Five times the smallest of three consecutive even integers is 10 more than twice the largest. find the integers?
5872345098234783904672083946728390752430689723409687298290843 theres your answer
Sum of three consecutive multiples of 8 is 888 find the multiples?
8A + (8A+8) + (8A+16) = 888 24A + 24 = 888 ===> 24A = 864 ===> A = 36 The multiples are 8A, 8A+8, 8A+16 = 288, 296, 304. Sum = 888.
Find 3 consecutive multiples of nine that add up to 243?
72, 81, 90
The sum of three consecutive multiples of 8 is 888 find the multiple?
The numbers must total 888/8 ie 111. The middle number is 1/3 of 111 ie 37 so the three numbers are 36, 37 and 38 and multiples are 288, 296 and 304.
How can you find the first three common multiples of the numbers by listing multiples?
vhghghghvv
Is it possible to find 5 consecutive numbers in multiples of 2345 and 6?
2, 3, 4, 5 and 6 are multiples of 2, 3, 4, 5 and 6.
How do you find three consecutive integers so that twice the first increased by three times the third will be -24?
The three integers, since they are consecutive, can be listed as a, a+1, and a+2. Twice the first is 2a. Three times the third is 3(a+2) = 3a+6. First make a formula of the information given: 2a+(3a+6)= -24 Next, solve the formula: 5a + 6 = -24 Subtract 6 from each side. 5a = -30 Divide each side by 5. a = -6 The three consecutive numbers are -6, -5, and -4.
