(x + 4)(x + 13)
(x+13)(x+4)
x3 + x2 - 17x + 15 = (x - 1)(x - 3)(x + 5). Thus, the zeros are 1, 3, and -5. All three zeros are rational.
It is x+9, provided that x is not -8.
Given that 52 - x2 + x = 10, then -52 + x2 - x + 10 = x2 - x - 42 = (x - 7)(x + 6) = 0. Therefore, x = 7 or -6.
(x + 4)(x + 13)
(x+13)(x+4)
x3 + x2 - 17x + 15 = (x - 1)(x - 3)(x + 5). Thus, the zeros are 1, 3, and -5. All three zeros are rational.
It is x+9, provided that x is not -8.
(x + 1)(x + 3)(x - 5)
(x + 3)(4x + 5)
x2 + y - 52 = 30x2 - x2 + y - 52 + 52 = - x2 + 30 + 52y = -x2 + 82Since a = -1, the parabola open downward, and crosses the x-axis at x = +&- sq.root of 82.0 = -x2 + 820 - 82 = -x2 + 82 - 82-82 = -x282 = x2+&- sq.root of 82 = x
Given that 52 - x2 + x = 10, then -52 + x2 - x + 10 = x2 - x - 42 = (x - 7)(x + 6) = 0. Therefore, x = 7 or -6.
3x2 + 17x + c = 0, rearranging gives c = -3x2 - 17x
Complete the squares: x2 - 10x + 25 + y2 + 4y + 4 - 52 = 25 + 4 = 29 x2 - 10x + 25 + y2 + 4y + 4 = 52 + 29 = 81 So the radius is sqrt(81) = 9
x3-x2+5x-1 with remainder 7, which the final answer would be written as:x3-x2+5x-1+[7/(4x+3)]
It is 1.17x