-10
x2 + 20x + 4 = 0 x2 + 20x + 100 = 96 (x + 10)2 = 96 x + 10 = ±961/2 x = -10 ±961/2 x = -10 ±4√6
(x - 10)(x - 10)
4x2 - 20x + 16 = 4(x2 - 5x + 4) = 4(x - 1)(x - 4)
20x -5
If: y = x2+20x+100 and x2-20x+100 Then: x2+20x+100 = x2-20x+100 So: 40x = 0 => x = 0 When x = 0 then y = 100 Therefore point of intersection: (0, 100)
x2 + 20x - 39 = 0: Add 61 giving: x2 + 20x + 100 = (x + 10)2
-10
x2 + 20x + 4 = 0 x2 + 20x + 100 = 96 (x + 10)2 = 96 x + 10 = ±961/2 x = -10 ±961/2 x = -10 ±4√6
x2-20x+100 = (x-10)(x-10) when factored
(x - 10)(x - 10)
x2 + 20x +0 =30 [(20/2)2 =100] x2 + 20x + 100 =30 +100 √(x+10)2=√130 x+10=√130 x= −10+√130 √ means square root
4x2 - 20x + 16 = 4(x2 - 5x + 4) = 4(x - 1)(x - 4)
x2 + 9x2 = 10x2
x2 + 36 = 20x so x2 - 20x + 36 = 0 so x2 - 2x - 18x + 36 = 0 or x(x - 2) - 18(x - 2) = 0 that is (x - 2)(x - 18) = 0 so x - 2 = 0 or x - 18 = 0 ie x = 2 or x = 18
NO,because in quadratic equation highest power of a variable is 2. e.x. 4x2-20x+10=0.
If that first term is x2, the answer is (x - 10)(x - 10) or (x - 10)2