Taking the equation to be y=ax2 + bx +c , and using the formula x = -b plus/minus sqrt (b2-4ac), all over 2a: x = (-3+21)/12 or (-3-21)/12 so x = 1.5 or -2
Using the quadratic equation formula:- x = 3.795831523 or x = -5.795831523
X= (3/5 , -2)
It can be solved by using the quadratic equation formula.
By using the quadratic equation formula
By using the quadratic equation formula: x = -5 and x = 3
x^(2) - 10x + 16 = 0 Factors of '16', which are, 1,2,4,8,16. Select two numbers from this list that add/subtract to '10' . They are '2' and '8'. Setting up brackets ( x 2)(x 8) Since '16' is positive(+), then both signs must be the same. Since '10x' is negative (-) , then both signs are negative. Hence (x - 2)(x - 8 ) = 0 When x - 2 = 0 x = 2 & when x - 8 = 0 x = 8 So the two answers are ,2, & ,8, .
Using the quadratic equation formula:- x = 3.795831523 or x = -5.795831523
X= (3/5 , -2)
It can be solved by using the quadratic equation formula.
a2+30a+56=0 , solve for a Using the quadratic formula, you will find that: a=-2 , a=-28
By using the quadratic equation formula
By using the quadratic equation formula: x = -5 and x = 3
For any quadratic ax2 + bx + c = 0 we can find x by using the quadratic formulae: the quadratic formula is... [-b +- sqrt(b2 - 4(a)(c)) ] / 2a
2x2-10+7 = 0 Solving the quadratic equation using the quadratic formula will give you two solutions and they are: x = (5 - the square root of 11)/2 or x = (5 + the square root of 11)/2
-34
x = 7/2 and also x = -3/2 by using the quadratic equation formula.
Using the quadratic equation formula: x = 8.42 or x = -1.42