cos(pi) = -1 so the equation becomes x = -y2.
That is equivalent to y = sqrt(-x)
The domain of this function is x ≤ 0.
The graph of the function is the same as that of a unit parabola in the first quadrant rotated anticlockwise by pi/2 radians.
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Either you mean "cos(x) multiplied by pi", (i.e pi*cos(x)) or "cos(pi)" (i.e cosine of pi), but it is unclear which you mean from the question. Please clarify.
area equals pi r squared therefor r squared equals area over pi. Now find square root of r squared and you have "R" (radius) = 2.821
c2 = g lambda / 2 pi
no, the area of a circle equals pi times the radius squared or circumference times diameter over four.
either cos OR tan-sin equals zero socos=0 at pi/2 and 3pi/2ortan=sin which is impossibleim not sure though