10x+7 = 5x+32 10x-5x = 32-7 5x = 25 x = 5
It is an equation and the value of x is 32/3
7x - 12y = any other number.
13x+27=3x+32 Reorder 13x-3x=32-27 Simplify 10x=5 Simplify x=5/10 Simplify x=1/2 Answer
Let's solve that one together, boys and girls! Ready ?b - 32 = 78Add 32 to each side of the equation:b = 110That was fun.
If you mean: 32-10x+7y = 0 then as a straight line equation it is 7y = 10x-32
10x+7 = 5x+32 10x-5x = 32-7 5x = 25 x = 5
n=-32
2y= 32 y=16
b-30=32 b=30+32 b=62
27
30/2 = 32? since 30/2 equals 15, and not 32, this is an untrue equation. please resubmit correctly.
There are 2 roots to the equation x2-4x-32 equals 0; factored it is (x-8)(x+4); therefore the roots are 8 & -4.
To solve the equation 4x = 32, we need to isolate the variable x. We can do this by dividing both sides of the equation by 4, since division is the inverse operation of multiplication. Therefore, x = 32 / 4, which simplifies to x = 8. So, the value of x that satisfies the equation 4x = 32 is 8.
The equation to solve for this is x * 16 = 32. To find the value of x, you would divide both sides of the equation by 16. Therefore, x = 32 / 16, which simplifies to x = 2. So, 2 times 16 equals 32.
The equation of the circle with center (h, k) and radius r is of the form(x - h)2 + (y - k)2 = r2x2 + y2 - 10x + 6y = 47 (complete the square)[x2 - 10x + (10/2)2] + [y2 + 6y +(6/2)2] = 47 + (10/2)2 +(6/2)2(x2 - 10x + 52) + (y2 + 6y + 32) = 47 + 52 + 32(x - 5)2 + (y + 3)2 = 81(x - 5)2 + (y + 3)2 = 92So that the center of the circle is (5, -3) and the radius is 9.
It is an equation and the value of x is 32/3