2y= 32
y=16
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If: 3x+2y = 5x+2y = 14 Then: 3x+2y = 14 and 5x+2y =14 Subtract the 1st equation from the 2nd equation: 2x = 0 Therefore by substitution the solutions are: x = 0 and y = 7
2y = 6x - 8y = 3x - 4========m(slope) = 3=========
you can not solve this equation
3x - 2y = 20 Substitute x = 4y into this equation: 3(4y) - 2y = 20 ie 12y - 2y = 20 10y = 20 so that y = 2 and then x = 4y gives x = 2*4 = 8
-2x + 2y = 4 is equivalent to twice -2 + y = 2 which is the equation of a straight line.