If: 3x+2y = 5x+2y = 14 Then: 3x+2y = 14 and 5x+2y =14 Subtract the 1st equation from the 2nd equation: 2x = 0 Therefore by substitution the solutions are: x = 0 and y = 7
since Y=8 and your equation is 2Y then it would be 2X8=16.
2y = 6x - 8y = 3x - 4========m(slope) = 3=========
3x - 2y = 20 Substitute x = 4y into this equation: 3(4y) - 2y = 20 ie 12y - 2y = 20 10y = 20 so that y = 2 and then x = 4y gives x = 2*4 = 8
you can not solve this equation
The equation is -2y + 16 = 10
3x + 2y = 8 This is an equation. It could be the equation of a line.
2y-3x=4
what is the slope of the line that has the equation 4x+2y=12?
If: 3x+2y = 5x+2y = 14 Then: 3x+2y = 14 and 5x+2y =14 Subtract the 1st equation from the 2nd equation: 2x = 0 Therefore by substitution the solutions are: x = 0 and y = 7
4x + 2y = 6 (first equation x 2) 4x + 2y = 6 (second equation rearranged) No unique answer exists
-6y + 14 + 4y = 32-2y = 32 - 14-2y = 18y = - 9
since Y=8 and your equation is 2Y then it would be 2X8=16.
5x 2y = 10
If: 3x+2y = 5x+2y = 7 Then: 3x+2y = 7 and 5x+2y = 7 Subtract the 1st equation from the 2nd equation: 2x = 0 or x = o By substitution: x = 0 and y = 3.5
-2x - 2y = -122x + 2y = 122y = 12 - 2xy = 6 - x
Yes.