x[x+1] squared Simplified is, to my knowledge, x squared plus ( x + 1) squared
Since the problem has 4 terms, first you factor x cubed plus 9x squared, then you factor 2x plus 18. So when you factor the first two term, you would get x sqaured (x plus 9). Then when you factor the last two terms and you get 2 (x plus 9). Ypure final answer would be (x squared plus 2)(x plus 9)
That can be factored to (x - 2)(x - 1)
(a + x^2)(b + y^2)
x < 2 or x > 8.
By factoring I get x-3 divided by x+3
it equals x1 it equals x1
(x-1)(x+2)
x[x+1] squared Simplified is, to my knowledge, x squared plus ( x + 1) squared
Well, honey, x squared plus 6x is a polynomial expression that can be simplified by factoring out an x. So, the answer is x(x + 6). Now go forth and conquer those math problems like the boss you are!
Since the problem has 4 terms, first you factor x cubed plus 9x squared, then you factor 2x plus 18. So when you factor the first two term, you would get x sqaured (x plus 9). Then when you factor the last two terms and you get 2 (x plus 9). Ypure final answer would be (x squared plus 2)(x plus 9)
Let square = [x] -4+3*(-2)*[-4]+[3x-2x]=-4-6-2+[x]=-12+[x]The answer is negative 12 plus squared x.
That can be factored to (x - 2)(x - 1)
(a + x^2)(b + y^2)
(x+y)2
x < 2 or x > 8.
One plus cosecant squared x is equal to cotangent squared x.