I suppose the full question is:
Given the following system of equations, find the values of x and y.
x+y=2
x+2y=-10
First, you need to isolate the variable y in the equation x+y=2
You do this by subtracting x from both sides of the equation.
x+y-x=2-x
Simplify:
y=2-x
Now you substitute the equation 2-x in the place of y in the equation x + 2y=-10
Like this:
x+2y=-10
x+2(2-x)=-10
Distribute the two:
x+4-2x=-10
Combine like terms:
-x+4=-10
Subtract 4 from both sides:
-x+4-4=-10-4
Simplify:
-x=-14
Divide both sides by negative one to get rid of the negative sign in front of x:
-x/-1=-14/-1
Simplify:
x=14
Plug the value of x (14) into the equation x+y=2:
14+y=2
Subtract 14 from both sides:
14-14+y=2-14
Simplify:
y=-12
Now you are done.
From now on, please pay attention in class.
If you don't even know the basic math skills that this requires then you have no future.
The equation is -2y + 16 = 10
(2, -1)
2y(x+2)=
4y+2 = 2y+6 4y-2y = 6-2 2y = 4 y = 2
The values are: x = -6 and y = 10
The equation is -2y + 16 = 10
(2, -1)
2y(x+2)=
2y = -10y = -58 - 2x - 2(-5) = -108 - 2x + 10 = -10-2x = -10 - 182x = 28x = 14Check:2y = 8 - 2x - 2y = -102(-5) = 8 - 2(14) - 2(-5) = -10-10 = 8 - 28 + 10 = -10-10 = -20 + 10 = -10-10 = -10 = -10
4y+2 = 2y+6 4y-2y = 6-2 2y = 4 y = 2
No 2y-3 is not equals y plus 2AND how old are u?
(3, 2)
The values are: x = -6 and y = 10
2y+26 = 28 2y = 28-26 2y = 2 y = 1
y=2.5 and x=5
Exactly (2y + 4) .
(2, 1)