If: y2+x2 = 52 Then: x2 = 52-y2 Their values could be: x = 3 and y = 4
y = x + ex then dy/dx = 1 + ex and d2y/dx2 = ex
It's an equation. Specifically, in 3 dimensions it's the equation of a right cone centered on the origin.
369
X + Y⁶X + Y * Y * Y * Y * Y * Y
15
If: y2+x2 = 52 Then: x2 = 52-y2 Their values could be: x = 3 and y = 4
... and what is the question?
999 and 1
(x+y)power 2 -2xy
y = x + ex then dy/dx = 1 + ex and d2y/dx2 = ex
It's an equation. Specifically, in 3 dimensions it's the equation of a right cone centered on the origin.
(x+y)^2+z^2=x^2+y^2+z^2+2xy or ((x+y)^2+z)^2= (x^2+y^2+2xy+z)^2= x^4+y^4+z^2+6x^2y^2+4x^3y+2x^2z^2+4xy^3+4xyz^2+2z^2y^2
369
-8
X + Y⁶X + Y * Y * Y * Y * Y * Y
x2 + 121y2 = x2 - (-121)y2 = x2 - (11iy)2 = (x - 11iy)(x + 11iy)