That factors to (x - 3)(x + 6)
The given expression can be simplified to: 3X squared +27
(3x-2)(x-2)
(x - 3)(x^2 + 6)
20x2 - 3x + 10 does not have any real factors.
Factorise it: (x + 5)(3x - 8)
x^2 + 3x + 2/(-3x) - x^2 - 2=3x-2+2/(-3x)=3x-2-2/(3x)
3x^(2) +9x - 2x -6 Collect 'like terms'. Hence 3x^(2) + 7x - 6 Next write down all the factors of '3' and '6' Hence 3 ; 1' & 3' 6 ; 1,6 ; 2,3. From these pairs of number we select a pair from each coefficient, that add/multiply to '7' . Hence (3' x 3 ) & (1' x 2) ; NB 'dashes' (') to indicate source of numbers. Write up brackets (3x 2)(x 3) -2)(x + 3) Next we notice that the '6' is negative, so the two signs are different (+/-) The '7x' is positive , so the larger number takes the positive sign . Hence (3x - 2)(x + 3)
The given expression can be simplified to: 3X squared +27
(3x-2)(x-2)
3x squared minus 25x minus 28
9x2 - 6xy + y2 - 81 = (3x - y)2 - 92 = (3x - y - 9)(3x - y + 9)
(x + 2)(3x - 1)(3x + 1)
(x - 3)(x^2 + 6)
If that's -18y2, the answer is (3x - 2y)(x + 9y)
3x^2 -14x +15 = (3x-5)(x-3)
20x2 - 3x + 10 does not have any real factors.
9x2 - 6xy + y2 - 81 = (3x - y)2 - 81 = (3x - y - 9)*(3x - y + 9)