p3(p + 1)(p + 12)
(x2 + 1)(x2 - 2)
A trinomial will be completely factorised when it has three terms involving the unknown to the power of 1. eg x³ - 6x² + 11x - 6 = (x - 1)(x - 2)(x - 3) eg x³ - 3x² + 2x = x(x - 1)(x - 2) eg x³ - x² = x²(x - 1) = x(x - 1)x
do you mean x2 + 3x + 2 ? Factors are (x +2)(x+1)
1/8
When there is no x term with a higher power than 1. Once all x-terms have a power of 1 or below, the expression has been fully factorised.
A completely factored form is one which is composed of product of factors and can't be factorized further. Let us consider two examples: x2 - 4x + 4 is not a factored form because it can be factored as (x - 2)(x - 2). (x +1)(x2 - 4x + 4) is also not a factored form because x2 - 4x + 4 can be factored further as (x - 2)(x - 2). So, the completely factored form is (x + 1)(x - 2)(x - 2).
6x2+5x+1 = (3x+1)(2x+1) when factored
p3(p + 1)(p + 12)
3y4 + 3y2 = 3y2(y2 + 1)
(x2 + 1)(x2 - 2)
4(1 - 4x + 7y)
-1
So x4 - 1 is the difference of squares, so x4 - 1 = (x2 - 1)(x2 + 1) = (x + 1)(x - 1)(x2 + 1).
66 factored to get -1 = 65
5x^2 - 5 = 5(x^2 - 1) = 5(x - 1)(x + 1)
It is (3x-1)(x+5) when factored