If x/3 = 9, then x = 27.
x/3 - 2 = 9 x/3 = 11 x = 33
To find the quotient when (2x^2 + 3x - 9) is divided by (x^3), we note that the degree of the divisor (x^3) is greater than the degree of the dividend (2x^2 + 3x - 9). Therefore, the quotient is (0) since (x^3) cannot divide (2x^2 + 3x - 9) without resulting in a fractional expression.
x/3 - 9 = 18 x = 81
9/x
x/9
x/3 - 2 = 9 x/3 = 11 x = 33
x/3 - 9 = 18 x = 81
let X = number quotient = x/4 x/4 + 9 = 12 x/4 = 3 x = 12
9/x
x/9
9
4 + x/3 ≥ 9 x/3 ≥ 5 x ≥ 15
If the number is x then: x+4-9 = -2 and so x = 3
3/x
It is x/9 - 7.
2x4 - 9x3 + 13x2 - 15x + 9 = 2x4 - 6x3 - 3x3 + 9x2 + 4x2 - 12x - 3x + 9 = 2x3(x - 3) - 3x2(x - 3) + 4x(x - 3) - 3(x - 3) = (x - 3)*(2x3 - 3x2 + 4x - 3) So the quotient is (2x3 - 3x2 + 4x - 3) and the remainder is 0.
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