x = -2 and y = 3
y=x+2 is also equal to y-2=xy = x + 2 , they have to be given what either x or y is and then you'd solve for the other one
The variable 'x' would equal (8-y)/2. The variable 'y' would equal 8-2x.
(-3,-4)
5x + 3y - 2 - x + y + 2 = 4x + 4y = 4(x + y)
(x^2 - y^2)
Only when X or Y = 0 That is because (x + y) squared = x^2 + 2xy + y^2 x^2 + 2xy + y^2 = x^2 + y^2 when x or y = 0
x = -2 and y = 3
If x+y = 3 and y times x = 2 then y = 1.
-x+y = 1 -2+y = -2 y = 1+x y = -2+2 => y = 0 By sustituting the values of x and y can be found x = -1 and y = 0 Remember that a minus from a minus is equal to a plus. So - -1+0 = 1
x = 4 and y = 6
y=x+2 is also equal to y-2=xy = x + 2 , they have to be given what either x or y is and then you'd solve for the other one
you need to know the x or y value
No it equals 6 because x and y equal 1 in themselves
That would be very hard to answer, because it's not. (x + y)2 = x2 + y2 + 2xy
If you mean y = x+4 and y = x-2 then the slopes would be parallel but with different y intercepts
The variable 'x' would equal (8-y)/2. The variable 'y' would equal 8-2x.