c
y' = (sec(x))^2
x = y = 0 ?
Can you help with this equation? Thanks. Solve for x and y and z for the following. x plus y plus z equals 9 x plus 2y plus 3z equals 23 x plus 5y plus -3z equals -7
73474949444999272725678251628909813.345267777777776663
x + y + z = 0 x = a - b, y = b - c, z = c - a, therefore a - b + b - c + c - a = ? a - a + b - b + c - c = 0
c
It is the intercept: the value that y takes when x = 0
y' = (sec(x))^2
x = 14
x = y = 0 ?
Can you help with this equation? Thanks. Solve for x and y and z for the following. x plus y plus z equals 9 x plus 2y plus 3z equals 23 x plus 5y plus -3z equals -7
multiply a by x then add the product of c and y. Your answer would be, based on the value of a,x,c,y, like this.ax + cy = ??
73474949444999272725678251628909813.345267777777776663
(1, 9)
y equals x plus 5 is the equation of a straight line in the x-y plane.
y equals x plus 4 when y equals 0 then x equals 2i i is the square root of negative 1