it depends,if y = 0 the answer is -12 if y = 5 then the answer is 368
(y-2) (x+4)
It is a quadratic equation in the form of y2-4y-5 = 0 and will have two solutions: When factorised: (y-5)(y+1) = 0 Therefore: y = 5 or y = -1
y2-4y-32 = (y+4)(y-8) when factored
If: -4y+7 = 35-6 then y = -5.5
it depends,if y = 0 the answer is -12 if y = 5 then the answer is 368
(y-2) (x+4)
It is a quadratic equation in the form of y2-4y-5 = 0 and will have two solutions: When factorised: (y-5)(y+1) = 0 Therefore: y = 5 or y = -1
y2-4y-32 = (y+4)(y-8) when factored
4(y - 3)(y + 3)
-6 + 3x - y - 4x + 4y + 5 (combine like terms) = (-6 + 5) + (3x - 4x) + (-y + 4y) = -1 - x + 3yHope this helps :)
If: -4y+7 = 35-6 then y = -5.5
Your question is unanswerable until you know what x & y are.
4y-12x=8 You can't get values for y and x, but if you wanted the equation of a line, find y =mx+b form. 4y = 12x +8 Divide each side by 4 y = 3x + 2
5x + 4y - 8 = 0Alright, we want to get this in y = mx + b formsubtract 4y from each side-4y = 5x - 8divide each side by -4y = -0.8x + 2in y = mx + b form, b is the y-intercept and m is the slope.m directly affects x, while b moves it up and down the y-axis about the origintherefore, in this problem the slope is -0.8
7x-4y = 26 5x-4y = 14 Subtract the bottom equation from the top squation remembering that a minus minus is equal to a plus therefore - 4y - - 4y = 0 2x = 12 Divide both sides by 2 to find the value of x: x = 6 Substitute the value of x into the original equations to find the value of y: Therefore: x = 6 and y = 4
The answer to x2 - 2x - 4y2 - 4y =(x - 2y)(x - 2y - 2)