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If X plus Y equals 15 and X minus Y equals 5 what is X times Y minus X plus Y?
Your question is like this:X+Y=15, X-Y=5, (X x Y)-X+Y= ?According to my calculations, X=10 and Y=5, therefore (X x Y)-X+Y= 45.
Y equals 2x y-x equals 5 using the sudstitution method?
-3
Is x-y equals 5 a function and how?
X - Y = 5 - Y = - X + 5 Y = X - 5 ==========Now it is a function because it passes the vertical line test.
How do you solve x plus y equals 5 for y?
y=5-x
How do you turn X equals 5 plus y into ordered pairs?
Put in function form. X = 5 + Y 5 + Y = - X Y = - X - 5 ==================The ordered pairs.
If the sum of 2 numbers is 4.5 and their product is 5 what is the 2 numbers?
Let x = one number = 2 or 2.5 Let y = the other number = 2.5 or 2 (x)(y)=5 x+y=4.5 y=4.5-x (x)(y)=5 (x)(4.5-x)=5 4.5x-x^2-5=0 I used the quadratic formula to get x. x=2 or x=2.5 (x)(y)=5 (2)(y)=5 y=5/2 y=2.5 (x)(y)=5 (2.5)(y)=5 y=5/2.5 y=2
X the power of 4 times y times x to the power of 5 times y?
x^(4)*y*x^(5)*yMultiply x^(4) by y to get x^(4)y.(d)/(dx) x^(4)*y*x^(5)*y=x^(4)y*x^(5)*yMultiply x^(4)y by x^(5) to get x^(9)y.(d)/(dx) x^(4)*y*x^(5)*y=x^(9)y*yMultiply x^(9)y by y to get x^(9)y^(2).(d)/(dx) x^(4)*y*x^(5)*y=x^(9)y^(2)To find the derivative of x^(9)y^(2), multiply the base (x) by the exponent (9), then subtract 1 from the exponent.(d)/(dx) x^(4)*y*x^(5)*y=9x^(8)y^(2)The derivative of x^(4)*y*x^(5)*y is 9x^(8)y^(2).9x^(8)y^(2)
What is y equals x plus 2 when x equals -1 and y equals 5?
If [ y = x + 2 ], then x is not -1 when y = 5.If [ y = x + 2 ],then when x = -1, y = 1,and when y = 5, x = 3.
What is Y x plus 5 Y 6?
The answer to Y x plus 5 Y 6 is Y(x+5Y5).One possible solution to y x plus 5 y 6 is Y(x+5Y5).
If X plus Y equals 15 and X minus Y equals 5 what is X times Y minus X plus Y?
Your question is like this:X+Y=15, X-Y=5, (X x Y)-X+Y= ?According to my calculations, X=10 and Y=5, therefore (X x Y)-X+Y= 45.
How do you graph x plus y equals 5 and x plus y equals 6?
you subtract x from both sides for both equations to get it in y= form. so... x+y=5 x+y-x=5-x y=5-x x+y=6 x+y-x=6-x y=6-x thanks:D but i meant with absolute value signs it was supposed to look like this : |x+y|=5 and |x|+|y|=6 ... but when i typed it in answers.com changed it
Y equals 2x y-x equals 5 using the sudstitution method?
-3
Is x-y equals 5 a function and how?
X - Y = 5 - Y = - X + 5 Y = X - 5 ==========Now it is a function because it passes the vertical line test.
Y equals -x plus 12x-y equals 5 solve by substitution?
17
How do you solve x plus y equals 5 for y?
y=5-x
How do you turn X equals 5 plus y into ordered pairs?
Put in function form. X = 5 + Y 5 + Y = - X Y = - X - 5 ==================The ordered pairs.
What is the answer to x equals 5-y?
well, if 5-y=x, then y=x+5. basically that is only used for graphing.
