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It is (6, -1).
Without a second independent equation, it's not a 'system' yet.
Without a second independent equation, it's not a 'system' yet.
I'm assuming the equation is: yx + 3y = 6 Now, you aren't going to get one answer for this, but you can factor for either x or y. In terms of y, this is y(x + 3) = 6 or y = 6/(x+3) In terms of x, this is yx = 6 - 3y or x = 6/y - 3 If you graph these, you'll get a y=1/x type function with the vertical asymptote at x=-3
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