associative? single replacement
Without an equality sign the information given can't be considered as an equation
The probability of ac and bc is 1/5.
There is no distributive property of addition over multiplication. The equation works if a + (b * c) = (a + b)*(a + c) = a2 + ab +ac +bc => a + bc = a2 + ab +ac +bc ie a = a2 + ab + ac = a*(a+b+c) and that, in turn requires that a = 0 or a+b+c = 1 If a, b and c are fractions than the second condition requires the fractions to sum to 1 - not be equal to 1.
(a + b)/(a - b) = (c + d)/(c - d) cross multiply(a + b)(c - d) = (a - b)(c + d)ac - ad + bc - bd = ac + ad - bc - bd-ad + bc = -bc + ad-ad - ad = - bc - bc-2ad = -2bcad = bc that is the product of the means equals the product of the extremesa/b = b/c
A+BC+AC+B=A+BC+AC+B unless any of these variables has an assigned value.
associative? single replacement
associative? single replacement
Without an equality sign the information given can't be considered as an equation
A general equation showing one nonmetal replacing another nonmetal in a compound is represented by the following formula: A + BC -> AC + B. Here, element A (a nonmetal) displaces element B in compound BC to form a new compound AC.
A single replacement reaction equation consists of a reactant compound and a new product compound formed by the replacement of an element in the reactant with another element. The general form is: A + BC -> AC + B, where A and B are elements, and BC is a compound.
The probability of ac and bc is 1/5.
There is no distributive property of addition over multiplication. The equation works if a + (b * c) = (a + b)*(a + c) = a2 + ab +ac +bc => a + bc = a2 + ab +ac +bc ie a = a2 + ab + ac = a*(a+b+c) and that, in turn requires that a = 0 or a+b+c = 1 If a, b and c are fractions than the second condition requires the fractions to sum to 1 - not be equal to 1.
a+bc --> ac+b
.Ab + c cb + a
(a + b)/(a - b) = (c + d)/(c - d) cross multiply(a + b)(c - d) = (a - b)(c + d)ac - ad + bc - bd = ac + ad - bc - bd-ad + bc = -bc + ad-ad - ad = - bc - bc-2ad = -2bcad = bc that is the product of the means equals the product of the extremesa/b = b/c
A+bc---> b+ac