Do you mean F = abc + abc + ac + bc + abc' ? *x+x = x F = abc + ac + bc + abc' *Rearranging F = abc + abc' + ab + bc *Factoring out ab F = ab(c+c') + ab + bc *x+x' = 1 F = ab + ab + bc *x+x = x F = bc
It would be a straight line of length bc
hello
(a + b)/(a - b) = (c + d)/(c - d) cross multiply(a + b)(c - d) = (a - b)(c + d)ac - ad + bc - bd = ac + ad - bc - bd-ad + bc = -bc + ad-ad - ad = - bc - bc-2ad = -2bcad = bc that is the product of the means equals the product of the extremesa/b = b/c
You could conclude that B lies between A and C.
associative? single replacement
A+BC+AC+B=A+BC+AC+B unless any of these variables has an assigned value.
yes because ab plus bc is ac
This is a 'Sngle Displacement' reaction ( A + BC --> AC + B
It is possible, depending on what on earth AC and BC are!
A+bc---> b+ac
A+bc---> b+ac
(a + b)(b + c)
never A+ :))
Do you mean F = abc + abc + ac + bc + abc' ? *x+x = x F = abc + ac + bc + abc' *Rearranging F = abc + abc' + ab + bc *Factoring out ab F = ab(c+c') + ab + bc *x+x' = 1 F = ab + ab + bc *x+x = x F = bc
It would be a straight line of length bc
hello