If P is 50% of Q, this means that P is half the value of Q. Similarly, if Q is 50% of R, then Q is half the value of R. Therefore, P is 25% of R, as it is 50% of Q, which is itself 50% of R. Thus, we can conclude that P is less than both Q and R.
Law of Syllogism If p->q and q->r are true conditionals, then p -> r is also true. (P)If people live in Manhattan, (q) then they live in New York. (q)If people live in New York, (r) then they live in the United States. Law of Detachment IF p-> q is a true conditional and p is true, then q is true. If you break an item in a store, you must pay for it. (P) Jill broke a vase in Potter's Gift Shop. (q) Jill must pay for the vase.
The answer is Q.
Unfortunately, the browser used for posting questions is hopelessly inadequate for mathematics: it strips away most symbols. All that we can see is "If p q and q r then p r.?". There is no operator between the variables. Some operators are transitive, others are not. In the case of the operator "is not equal to", the answer is that it depends. In the case of "is the parent of" the answer is no.
Suppose the radius is r and the bearings of the two points, P and Q are p and q respectively. Then the coordinates of P are [r*cos(p), r*sin(p)] and the coordinates of Q are [r*cos(q), r*sin(q)]. The distance between these two points can be found, using Pythagoras: d2 = (xq - xp)2 + (yq - yp)2 where xp is the x-coordinate of P, etc.
Law of Detachment also known as Modus Ponens (MP) says that if p=>q is true and p is true, then q must be true. The Law of Syllogism is also called the Law of Transitivity and states: if p=>q and q=>r are both true, then p=>r is true.
Converse: If p r then p q and q rContrapositive: If not p r then not (p q and q r) = If not p r then not p q or not q r Inverse: If not p q and q r then not p r = If not p q or not q r then not p r
Ifp < q and q < r, what is the relationship between the values p and r? ________________p
If P is 50% of Q, this means that P is half the value of Q. Similarly, if Q is 50% of R, then Q is half the value of R. Therefore, P is 25% of R, as it is 50% of Q, which is itself 50% of R. Thus, we can conclude that P is less than both Q and R.
A rational number is a number of the form p/q where p and q are integers and q > 0.If p/q and r/s are two rational numbers thenp/q + r/s = (p*s + q*r) / (q*r)andp/q - r/s = (p*s - q*r) / (q*r)The answers may need simplification.
If p->q, then the law of the contrapositive is that not q -> not p
Law of Syllogism If p->q and q->r are true conditionals, then p -> r is also true. (P)If people live in Manhattan, (q) then they live in New York. (q)If people live in New York, (r) then they live in the United States. Law of Detachment IF p-> q is a true conditional and p is true, then q is true. If you break an item in a store, you must pay for it. (P) Jill broke a vase in Potter's Gift Shop. (q) Jill must pay for the vase.
P=q/r* * * * *The correct answer is P = k*q/r where k is the constant of proportionality.
The statement "P and Q implies not not P or R if and only if Q" can be expressed in logical terms as ( (P \land Q) \implies (\neg \neg P \lor R) \iff Q ). This can be simplified, as (\neg \neg P) is equivalent to (P), leading to ( (P \land Q) \implies (P \lor R) \iff Q ). The implication essentially states that if both (P) and (Q) are true, then either (P) or (R) must also hold true, and this equivalence holds true only if (Q) is true. The overall expression reflects a relationship between the truth values of (P), (Q), and (R).
Two fractions are similar if they have the same denominator.So if p/r and q/r are two such fractions, then p/r + q/r = (p+q)/r.
sylogism is a law of geometry that states that ifp implies q and q implies r then p implies rhope this is what you were looking for :-)
tan x