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P=q/r

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The correct answer is P = k*q/r where k is the constant of proportionality.

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Q: P varies directly as q and inversely as r?
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How would you go about solving this direct variation question and what is the answer- If P varies directly as the square of Q and the constant of variation is 6 what is the value of P when Q equals 12?

If P varies directly with the square of Q then the equation would be in the form of P = kQ2, where k is the constant of variation so the new equation would be: P = 6Q2, so when Q = 12 we have P=6*122, or P = 864


Let k be the constant of proportionality and let q r s and t be positive real number variables. If q varies directly with the cube of r inversely with s and inversely with the square root of t which o?

q = k*r^3/(s*sqrt(t))


Find an equation of joint variation if P varies jointly as q r and s One set of values is p equals 70 Q equals 7 R equals 5 and S equals 4?

If P varies directly with q, r and s then P = kqrs, where k is a constant. As 70 = k x 7 x 5 x 4 = 140k : k = 70/140 = 1/2 The equation of joint variation is P = ½qrs.


If p q and q r then p r. Converse statement B.A syllogism C.Contrapositive statement D.Inverse statement?

Converse: If p r then p q and q rContrapositive: If not p r then not (p q and q r) = If not p r then not p q or not q r Inverse: If not p q and q r then not p r = If not p q or not q r then not p r


What is the sum or difference of p and q?

The sum of p and q means (p+q). The difference of p and q means (p-q).


What is the truth table for p arrow q?

Not sure I can do a table here but: P True, Q True then P -> Q True P True, Q False then P -> Q False P False, Q True then P -> Q True P False, Q False then P -> Q True It is the same as not(P) OR Q


What is q²-p² divided by q-p?

q + p


If p is 50 of q then what percent of p is q?

If p = 50 of q then q is 2% of p.


How do you write the negation of if and then?

If p then q is represented as p -> q Negation of "if p then q" is represented as ~(p -> q)


Simplify pp - q - q q - p?

p-q


What does p over q mean in algebra?

P! / q!(p-q)!


Why does multiplication or division with a negative number yield a negative answer?

The assertion in the question is not always true. Multiplying (or dividing) 0 by a negative number does not yields 0, not a negative answer.Leaving that blunder aside, let p and q be positive numbers so that p*q is a positive number.Thenp*q + p*(-q) = p*[q + (-q)] = p*[q - q] = p*0 = 0that is p*q + p*(-q) = 0Thus p*(-q) is the additive opposite of p*q, and so, since p*q is positive, p*(-q) must be negative.A similar argument works for division.