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The answer is probably 3y = 5x + k where k is any number but, with some symbols missing from the original equation, it is difficult to be certain.
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What is the equation of a line that passes through 3 -4 and is perpendicular to 5x -2y equals 3 on the Cartesian plane?
Perpendicular slope: -2/5 Perpendicular equation: y--4 = -2/5(x-3) => 5y--20 = -2x-3 => 5y = -2x-14 Perpendicular equation in its general form: 2x+5y+14 = 0
What is the equation passing through the point 3 -4 which is perpendicular to the line 5x -2y equals 3?
Known equation: 5x-2y = 3 or y = 5/2x -3/2 Slope of known equation: 5/2 Slope of perpendicular equation: -2/5 Perpendicular equation: y- -4 = -2/5(x-3) => 5y =-2x-14 Perpendicular equation in its general form: 2x+5y+14 = 0
What is the perpendicular bisector equation meeting the line segment of -4 8 and 0 -2?
2x -5y +19 = 0
What is the slope of a line perpendicular to the graph of the equation below 2.1x - 5y equals 6.9?
Gradient of given line is 2.1/5 = 21/50 So gradient (slope) of perpendicular is -50/21 = -2.381 (to 3 dp)
What is the equation to a line that is perpendicular to the graph of 5 x minus 3 y equals 9 and the two lines intersect at x equals 15?
It is 3x + 5y = 155 The slope of the line 5x -3y = 9: 5x - 3y = 9 → 3y = 5x - 9 → y = 5/3 x - 3 → slope is 5/3 → slope of perpendicular line is -3/5 Intercept at x = 15 → y = 5/3 x 15 - 3 = 22 → equation of perpendicular line is: y - 22 = -3/5 (x - 15) → 5y - 110 = -3x + 45 → 3x + 5y = 155
