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What is the equation of the line passing through -2 -3 that is at right angles to the equation 4x plus 3y -5 equals 0 on the Cartesian plane?
The equation will be perpendicular to the given equation and have a slope of 3/4:- Perpendicular equation: y--3 = 3/4(x--2) => 4y--12 = 3x--6 => 4y = 3x-6 Perpendicular equation in its general form: 3x-4y-6 = 0
What is the equation of a line that is perpendicular to and passes through the point (8 3)?
That depends on the equation that it is perpendicular too which has not been given but both equations will meet each other at right angles.
Could you write the equation of the line that is perpendicular to the line given that passes through the point shown?
Yes, I could, if I knew the slope of the line given.
The line given by the equation y equals -8x is perpendicular to what line?
It would be perpendicular to a line with the equation Y = 1/8 X.
What is the equation of a line that is perpendicular to and passes through the point (4 6)?
That would depend on its slope which has not been given.
What is the perpendicular equation that meets the line of 2 3 and 5 7 at its midpoint showing key aspects of work?
Here are the key steps:* Find the midpoint of the given line. * Find the slope of the given line. * Divide -1 (minus one) by this slope, to get the slope of the perpendicular line. * Write an equation for a line that goes through the given point, and that has the given slope.
How do I write the equation of the line that passes through the given point and is perpendicular to the given line Write the answer in slope-intercept form?
The standard equation for a straight line is y = mx + c. Let this be the equation of the original line. Note that m and c are known values. Let the given point coordinates be (a,b)Two straight lines are perpendicular if the product of their gradients (slopes) is -1.The slope (m1) of the perpendicular line is therefore m1 = -1/mWhen y = b then x = a so the equation for the perpendicular line is y = m1x + d, and substituting gives : b = -a/m + d and this will enable d to be calculated.NOTE : In the absence of information for the equation of the original line and the coordinates of the given point then this is a general rather than a specific answer.
The line given by the equation y equals 5x minus 2 is perpendicular to what equation?
It is: y = -1/5x-2
What is the equation of a line passing through (-6 5) and having a slope of?
The straight line equation would depend on the slope which has not been given.
What is the equation of the line passing through the given points 1 and 5 and 2 and 7?
Points: (1, 5) and (2, 7) Slope: 2 Equation: y = 2x+3
What is the straight line equation passing through -2 -3 that is perpendicular to 4x plus 3y -5 equals 0 showing all work?
The basic steps are:Solve the given equation for y. Since this puts the equation in slope-intercept form, you can immediately tell its slope from that equation.Divide -1 by this slope. This gives you the slope of the perpendicular line.Look up the equation for a line that has a given slope and passes through a given point. Apply it in this case.Another Answer:-If: 4x+3y-5 = 0Then: 3y = -4x+5 => y = -4/3x+5/3Perpendicular slope: 3/4Equation: y--3 = 3/4(x--2) => 4y--12 = 3(x--2) => 4y = 3x-6Or as: 3x-4y-6 = 0
Consider a uniform square plate of side a and mass m the moment of inertia of this plate about an axis perpendicular to its plane and passing through one of its corners is?
The moment of inertia of a uniform square plate of side a and mass m about an axis perpendicular to its plane and passing through one of its corners is given by I = (1/3)ma^2.
