To find the mass of 3.0 ml of gold, we can use the density of gold, which is approximately 19.32 grams per cubic centimeter (g/cm³). Since 1 ml is equivalent to 1 cm³, the mass can be calculated as follows: mass = density × volume = 19.32 g/cm³ × 3.0 cm³ = 57.96 grams. Therefore, 3.0 ml of gold has a mass of approximately 58 grams.
10001/999900
Since gold is 19.32 grams per ml and water is 1 gram per ml they both have the same mass
Density = mass / volumeDensity = 30 g / 8 ml = 3.75 g/ml
To find the mass of the gold sphere that displaces 2.3 mL of water, we can use the density of gold, which is approximately 19.32 g/cm³. Since 1 mL is equivalent to 1 cm³, the mass can be calculated using the formula: mass = density × volume. Therefore, the mass of the gold sphere is 19.32 g/cm³ × 2.3 cm³ = 44.49 grams.
Assuming the gold nugget is solid and pure (unlikely in real life!) The volume of the nugget is 77.0 - 50.0 mL = 27.0 mL So density = mass/volume = 521/27.0 = 19.3 g per mL.
You mean a volume of 30 ml and mass of 579 g. Its s density = mass/volume = 579/30 = 19.3 g/ml which is very heavy. It could be several choices, but GOLD is that density...
I'm not sure if you understand: 1mL is a way of measuring volume in metric, which can't be converted to mass. You might be able to find out what the mass of 1 mL of gold is by determining the density of that liquid. Density is usually expressed as g/mL. Then you merely do the math to detemine the grams of gold which would be the mass. For example, if the density of this gold liquid is 5.5 g/ml, then you know that the liquid contained 5.5 grams of gold - which would then be the mass of the gold.
10001/999900
One litre of water equals one kilogram of water
Since gold is 19.32 grams per ml and water is 1 gram per ml they both have the same mass
Density = mass / volumeDensity = 30 g / 8 ml = 3.75 g/ml
Density = Mass/Volume = 30/15 = 2 grams per mL.
To find the mass of the gold sphere that displaces 2.3 mL of water, we can use the density of gold, which is approximately 19.32 g/cm³. Since 1 mL is equivalent to 1 cm³, the mass can be calculated using the formula: mass = density × volume. Therefore, the mass of the gold sphere is 19.32 g/cm³ × 2.3 cm³ = 44.49 grams.
added, the total mass of the graduated cylinder becomes 80 g. This indicates that the mass of the 30 ml of water is 30 g, since the mass of the empty graduated cylinder is 50 g (80 g - 50 g = 30 g). Therefore, the water's density can be calculated as mass divided by volume, which is 30 g / 30 ml = 1 g/ml, consistent with the density of water.
The volume of gold displacing the water can be found using the density formula: density = mass/volume. Rearranging the formula to solve for volume, volume = mass/density. Plugging in the values given, volume = 100 grams / 19.3 grams per ml = 5.18 ml. So, the gold should displace 5.18 ml of water.
Assuming the gold nugget is solid and pure (unlikely in real life!) The volume of the nugget is 77.0 - 50.0 mL = 27.0 mL So density = mass/volume = 521/27.0 = 19.3 g per mL.
The mass of water added is 110 g minus the initial empty cylinder mass. The mass of the rock is the total mass of 250 g minus the mass of the water and empty graduated cylinder. The density of the rock can then be calculated using the mass of the rock and its volume (37 mL - 30 mL).