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What mass does 3.0 ml of gold have?
To find the mass of 3.0 ml of gold, we can use the density of gold, which is approximately 19.32 grams per cubic centimeter (g/cm³). Since 1 ml is equivalent to 1 cm³, the mass can be calculated as follows: mass = density × volume = 19.32 g/cm³ × 3.0 cm³ = 57.96 grams. Therefore, 3.0 ml of gold has a mass of approximately 58 grams.
What has a greater mass 19.32 ml of water or 1.0 ml of gold?
Since gold is 19.32 grams per ml and water is 1 gram per ml they both have the same mass
A nugget of gold with a mass of 521 g is added to 50.0 mL of water The water level rises to a volume of 77.0 mL What is the density of the gold?
Assuming the gold nugget is solid and pure (unlikely in real life!) The volume of the nugget is 77.0 - 50.0 mL = 27.0 mL So density = mass/volume = 521/27.0 = 19.3 g per mL.
What is the mass of 250 ml of water at 20 degrees C?
The density of water at 20 deg C (and at a pressure of 1 atmosphere) is 0.99820 so the mass is 250*0.99820 = 249.55 grams.
Would a teacup be 250 mL or 1 liter?
250 mL is a better bet.
