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If the sides AB, BC and CA of triangle ABC correspond to the sides DE, EF and FD of triangle DEF, then the two triangles are congruent if:AB = DE, BC = EF and CA = FD (SSS)AB = DE, BC = EF and angle ABC = angle DEF (SAS)AB = DE, angle ABC = angle DEF, angle BCA = angle EFD (ASA)If the triangles are right angled at A and D so that BC and EF are hypotenuses, then the triangles are congruent ifBC = EF and AB = DE (RHS)BC = EF and angle ABC = angle DEF (RHA).
"What else" implies there is already something that is congruent. But since you have not bothered to share that crucial bit of information, I cannot provide a more useful answer. no correct
Yes, triangles ABC and DEF are congruent if all corresponding sides and angles are equal. The congruence postulate that applies in this case could be the Side-Angle-Side (SAS) postulate, which states that if two sides and the included angle of one triangle are equal to two sides and the included angle of another triangle, then the triangles are congruent. Other applicable postulates include Side-Side-Side (SSS) and Angle-Angle-Side (AAS), depending on the known measurements.
Yes, triangles ABC and DEF can be considered equal (congruent) if they meet specific criteria, such as having all corresponding sides and angles equal. The postulate that applies in this case is the Side-Side-Side (SSS) Congruence Postulate, which states that if three sides of one triangle are equal to three sides of another triangle, the triangles are congruent. Other applicable postulates include Side-Angle-Side (SAS) and Angle-Side-Angle (ASA), depending on the given information.
Triangle ABC is simlar to Triangle DEF. AB divided by DE equals x. BC divided by EF also equals x. CA divided by FA also equals x. Note: It only works like this. When two similar or congruent triangles are named (eg Triangle ABC), the order of the capital letters is important.