All of the four-digit multiples of 400 end in 00.
A four-digit number that is divisible by 2, 5, and 9 must be divisible by their least common multiple, which is 90. The smallest four-digit number is 1000, and the largest is 9999. The smallest four-digit number divisible by 90 is 1080, while the largest is 9990. Therefore, any four-digit number like 1080 or 9990 can serve as an example.
A three-digit number that is divisible by both three and four must also be divisible by their least common multiple, which is twelve. The smallest three-digit number divisible by twelve is 108, and the largest is 996. Therefore, any three-digit number that is a multiple of twelve, such as 120, 144, or 480, will meet the criteria of being divisible by both three and four.
There can be no such number. If it is divisible by 5 and 6it must be divisible by 6.
To be divisible by 36 the number must be divisible by 9 (and 4). To be divisible by 9, the sum of the digits must be divisible by 9. 5 + 5 = 10 → need an extra 8 → A + B = 8.
Not necessarily. For example, the number 56 ends in a 6 but is not divisible by six. To check if a number is divisible by six, the number must be divisible by both 2 and 3. To check this, the last digit must be even and the sum of the digits must be divisible by three. If the number meets these conditions, it is in fact divisible by six.
A four-digit number that is divisible by 2, 5, and 9 must be divisible by their least common multiple, which is 90. The smallest four-digit number is 1000, and the largest is 9999. The smallest four-digit number divisible by 90 is 1080, while the largest is 9990. Therefore, any four-digit number like 1080 or 9990 can serve as an example.
A three-digit number that is divisible by both three and four must also be divisible by their least common multiple, which is twelve. The smallest three-digit number divisible by twelve is 108, and the largest is 996. Therefore, any three-digit number that is a multiple of twelve, such as 120, 144, or 480, will meet the criteria of being divisible by both three and four.
A number divisible by 123456789 must be 0 or bigger than 123456789. It must, therefore have 1 digit or 9 digits (or more). A remainder of 1 makes no difference to the number of digits. In any case, there can be no number of 4 digits that is divisible by 123456789.
Any number (however many digits) that is divisible by 3 and by 4 MUST be divisible by 6. So there cannot be a number that meets the requirements of the question.
yes 552 is divisible by 6 and the result is 92... to find out if a number is divisible by 6 then that number must be divisible by 2 and 3.. 1.If a number is divisble by three then the last digit must be divisible by 2 (so that the last digit must be 0,2,4,6,8) in this number the last digit is 2 so that it is divisible by 2 2.If a number is divisble by 3 then the sum of its digit must be divisible by 3. In this case the sum of the digits of 552 is 5+5+2= 12 and 12 is divisible by 3.... If this two rules fit in then that number is divisible by 6
There can be no such number. If it is divisible by 5 and 6it must be divisible by 6.
To be divisible by 36 the number must be divisible by 9 (and 4). To be divisible by 9, the sum of the digits must be divisible by 9. 5 + 5 = 10 → need an extra 8 → A + B = 8.
Not necessarily. For example, the number 56 ends in a 6 but is not divisible by six. To check if a number is divisible by six, the number must be divisible by both 2 and 3. To check this, the last digit must be even and the sum of the digits must be divisible by three. If the number meets these conditions, it is in fact divisible by six.
Look at the last digit of the number; if it is even then the number is divisible by 2, otherwise it is not.
No. If any number is divisible by 5 and 6, it must also be divisible by 30, which means that it must end with a zero.
A four-digit number that is divisible by both 5 and 9 must end in 0 or 5 (for divisibility by 5) and the sum of its digits must be divisible by 9 (for divisibility by 9). One example is 1080, as it ends in 0 and the sum of its digits (1 + 0 + 8 + 0 = 9) is divisible by 9. Another example is 1260, which also meets both criteria.
No. In order for a number to be divisible by 10, the ones digit must be zero (0).