To find a number between 130 and 140 that is exactly divisible by 12, we need to identify the multiples of 12 within that range. The multiples of 12 are 132 and 144. Since 144 is greater than 140, the number between 130 and 140 that is exactly divisible by 12 is 132.
135/9 = 15
No. As 6 is less than 130 it cannot be a whole number multiple of 130 so 6 is not divisible by 130. If you meant is 130 divisible by 6, then: 130 is even and 6 is even, so possibly, but 1 + 3 + 0 = 4 which is not divisible by 3, so 130 is not divisible by 3 and so not divisible by 6.
No because it is an even number which is divisible by 2 with no remainder
yes, it is a prime number, because it's factors are 1,130
136, 144, 152
181
135/9 = 15
No. As 6 is less than 130 it cannot be a whole number multiple of 130 so 6 is not divisible by 130. If you meant is 130 divisible by 6, then: 130 is even and 6 is even, so possibly, but 1 + 3 + 0 = 4 which is not divisible by 3, so 130 is not divisible by 3 and so not divisible by 6.
No because it is an even number which is divisible by 2 with no remainder
yes, it is a prime number, because it's factors are 1,130
Factors of 15 are 1, 3, 5 and 15. Starting with the greatest number, 15 is not divisible by 130. Then, 5 is both divisible by 130 and 10000. So the answer is 5.
136, 144, 152
There are 8 results: 110; 120; 130; 140; 150; 160; 170; 180.
1x 130= 130 2 x 65= 130
To find a number between 120 and 130 that is divisible by 3 and has a digit sum divisible by 4, we first consider the numbers in that range: 121, 122, 123, 124, 125, 126, 127, 128, 129. Next, we calculate the digit sum of each number: 121 (1+2+1=4), 122 (1+2+2=5), 123 (1+2+3=6), 124 (1+2+4=7), 125 (1+2+5=8), 126 (1+2+6=9), 127 (1+2+7=10), 128 (1+2+8=11), 129 (1+2+9=12). Therefore, the number between 120 and 130 that is divisible by 3 and has a digit sum divisible by 4 is 123.
No.
Yes - 130/2 = 65