No.
It is divisible by 10, but not by 235.
As 235 is ending by a 5 then it is divisible by 5 As 235 is not even it is not divisible by 2 As 2+3+5 is not divisible by 3, 235 is not divisible by 3 235/5 = 47 47 is prime so 235 = 5 * 47 and there's no other way to factorize it
235 and its multiples.
No. As 6 is less than 130 it cannot be a whole number multiple of 130 so 6 is not divisible by 130. If you meant is 130 divisible by 6, then: 130 is even and 6 is even, so possibly, but 1 + 3 + 0 = 4 which is not divisible by 3, so 130 is not divisible by 3 and so not divisible by 6.
To determine if 235 is divisible by 9, we sum its digits: 2 + 3 + 5 = 10. Since 10 is not divisible by 9, 235 is not divisible by 9. In order for a number to be divisible by 9, the sum of its digits must be divisible by 9.
No.
No.
1x 130= 130 2 x 65= 130
One: 235.
Yes - 130/5 = 26
Yes - 130/2 = 65
2 yes, the rest no.