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The most obvious answer would be 5, since 23,455 is divisible by 5 (as are all whole numbers that end in 5 or 0).

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Which number is completely divisible by 7 and by 23456 and gives remainder as 1?

The number would be (7x23456) + 1 = 164193


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23457 divided by 23456 leaves a remainder of 1, and it is divisible by 7. So that is one of infinitely many possible answers.


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