To find the least number divisible by 23456 with a remainder of 1, you need to find the least common multiple (LCM) of 23456 and the number 1 more than it. The LCM of two numbers is the smallest number that is a multiple of both numbers. In this case, you would calculate the LCM of 23456 and 23457. The LCM can be found by multiplying the two numbers and then dividing by their greatest common divisor.
Chat with our AI personalities
That's the number 1. The next-highest number which will have a remainder of 1 is 23456 + 1.
If you mean, by each of the numbers 2, 3, 4, 5, 6 separately, it is still one. To get the next one, get the least common multiple of all the numbers, and add that to one.
27836/56 gives 497 and 4 as quotient and remainder Dividend- remainder =27836-4 = 27832 which is divisible by 56. So the least no that to be subracted is 4
For a number to be divisible by another number it must be at least that number. As 3 is less than 605 it cannot be divisible by 605. Also 3 is not a FACTOR of 605, that is 3 does not divide into 605 without remainder.
For a number to be divisible by another number it must be at least that number. As 3 is less than 837 it cannot be divisible by 837. However, 3 IS a FACTOR of 837, that is 3 divides into 837 without remainder.
832/48 gives 17 as quotient and 16 as remainder. Dividend-remainder=divisor*quotient 832-16 = 48*17 which is 816 that is divisible by 48. So 16 to be subracted.
To find the least number that should be added to 924 to make it exactly divisible by 48, we need to find the remainder when 924 is divided by 48. The remainder is 12. Therefore, the least number that should be added to 924 to make it exactly divisible by 48 is 48 - 12, which equals 36.