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There is, in fact, no equation in the question, just three disjoint terms.
2c+(12-4)=20 Simplify the expression in the parentheses first. 2c+8=20 Subtract 8 from both sides of the equation. 2c=12 Divide both sides of the equation by 2. c=6
19
It is: 2c+8
12-2c = 2c add 2c to both sides 12 = 4c divide both sides by 4 3 = c
40 chickens and 30 pigsThis can be solved with 2 equations. Let p = the number of pigs and c = the number of chickens. Pigs and chickens each have 1 head, so p+c=70. Pigs have 4 legs and chickens have 2, so the total number of legs is 4p+2c=200.Solve this "system of equations" by substitution: The first equation can be written as p=70-c. Substitute the right side for p in the second equation:4(70 - c) + 2c = 200280 - 4c + 2c = 200280 - 2c = 200-2c = 200 - 280-2c = -80c = 40.Substitute this back into p=70-c: p=70-40=30.There are 40 chickens and 30 pigs.Check (in the words of the question): 40 chicken heads and 30 pig heads = 70 heads. 40x2=80 chicken legs, and 30x4=120 pig legs; 80+120=200 legs. Check!
2c+(12-4)=20 Simplify the expression in the parentheses first. 2c+8=20 Subtract 8 from both sides of the equation. 2c=12 Divide both sides of the equation by 2. c=6
-2c
2c + 4 - 3c = -9 + c + 5 -c + 4 = c - 4 -2c = -8 2c = 8 c = 4
19
It is: 2c+8
12-2c = 2c add 2c to both sides 12 = 4c divide both sides by 4 3 = c
-((3c - 4)(3c + 4)(2c - 5)(2c + 5))
40 chickens and 30 pigsThis can be solved with 2 equations. Let p = the number of pigs and c = the number of chickens. Pigs and chickens each have 1 head, so p+c=70. Pigs have 4 legs and chickens have 2, so the total number of legs is 4p+2c=200.Solve this "system of equations" by substitution: The first equation can be written as p=70-c. Substitute the right side for p in the second equation:4(70 - c) + 2c = 200280 - 4c + 2c = 200280 - 2c = 200-2c = 200 - 280-2c = -80c = 40.Substitute this back into p=70-c: p=70-40=30.There are 40 chickens and 30 pigs.Check (in the words of the question): 40 chicken heads and 30 pig heads = 70 heads. 40x2=80 chicken legs, and 30x4=120 pig legs; 80+120=200 legs. Check!
4 + 3c = 2c + 2Subtract 4 from each side:3c = 2c - 2Subtract 2c from each side:c = -2
Let c represent the number of chickens and p represent the number of pigs.Since chickens and pigs have one head each, 70 heads = c + p.Since chickens have 2 legs and pigs have 4 legs, 200 legs = 2c + 4p.Subtracting twice the first equation (140 = 2c + 2p) from the second, we get60 = 2porp = 30 pigsRewriting the first equation as c = 70 - p, we get c = 40 chickens.
If you mean: 2c+2+6c-4 then it is 8c-2 when simplified.
4c+1-5+2c = 6c-4.