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A 2 digit number that is the product of 2 consecutive integers and the sum of its digits is greater than the product of the digits both digits are even?
The 2-digit number must be 20, because it is the only 2-digit number whose sum of its two even digits, 2 + 0 = 2, is greater than the product of its two even digits, 2 x 0 = 0. Moreover, 20 is a product of the two consecutive integers 4 and 5.
What is the largest 2 digit number that is both prime and has prime numbers for both of its digits?
73 is the largest 2 digit number that is both prime and has prime numbers for both of its digits.
If n is an odd number then the number of digits in its square root will be?
I cannot see how odd or even will determine the number of digits in the square root. For example:100 is an even number, and its square root is 10 (2 digits)121 is an odd number, and its square root is 11 (2 digits)Maybe the question is not phrased properly for what the questioner is asking.
What is 3 digits plus 3 digits and equals 3 digits only using numbers 1 through 9 without carrying a number?
There is no solution to this problem. If each digit can be used once only then we have 5 odd numbered digits (1,3,5,7,9) and 4 even numbered digits (2,4,6,8). To create the two numbers that are added together requires the following combinations of digits. 5 Odd & 1 Even ....when added these will generate 2 Even digits & 1 Odd digit but the remaining digits are 3 Even. 4 Odd & 2 Even. These will generate 3 Even digits OR 1 Even digit & 2 Odd digits but the remaining digits are 1 Odd & 2 Even. 3 Odd & 3 Even. These generate 3 Odd digits OR 2 Even & 1 Odd digits but the remaining digits are 2 Odd & 1 Even. 2 Odd & 4 Even. These generate 3 Even digits OR 2 Odd & 1 Even digits but the remaining digits are 3 Odd & no Even.
What is the smallest digits prime number?
It is 2 which also is the only even prime number
When you divide the number by 5 the remainder is 4 the number has 2 digits and both digits are even the sum of the digits is 10?
64
A 2 digit number that is the product of 2 consecutive integers and the sum of its digits is greater than the product of the digits both digits are even?
The 2-digit number must be 20, because it is the only 2-digit number whose sum of its two even digits, 2 + 0 = 2, is greater than the product of its two even digits, 2 x 0 = 0. Moreover, 20 is a product of the two consecutive integers 4 and 5.
What is the largest 2 digit number that is both prime and has prime numbers for both of its digits?
73 is the largest 2 digit number that is both prime and has prime numbers for both of its digits.
What is the smallest 2-digits even number?
10
What number it digits decrease by 2 from the thousands place to the ones place and each number is even number?
If the digits go from the thousands place to the ones place then we need to use 4 digits. Because the digits are all even, we are forced to use the 4 even digits (2, 4, 6 and 8). As they decrease by 2 each time, the only option for ordering them is greatest to lowest. Therefore, the number described in the question is 8,642.
If n is an odd number then the number of digits in its square root will be?
I cannot see how odd or even will determine the number of digits in the square root. For example:100 is an even number, and its square root is 10 (2 digits)121 is an odd number, and its square root is 11 (2 digits)Maybe the question is not phrased properly for what the questioner is asking.
What is 3 digits plus 3 digits and equals 3 digits only using numbers 1 through 9 without carrying a number?
There is no solution to this problem. If each digit can be used once only then we have 5 odd numbered digits (1,3,5,7,9) and 4 even numbered digits (2,4,6,8). To create the two numbers that are added together requires the following combinations of digits. 5 Odd & 1 Even ....when added these will generate 2 Even digits & 1 Odd digit but the remaining digits are 3 Even. 4 Odd & 2 Even. These will generate 3 Even digits OR 1 Even digit & 2 Odd digits but the remaining digits are 1 Odd & 2 Even. 3 Odd & 3 Even. These generate 3 Odd digits OR 2 Even & 1 Odd digits but the remaining digits are 2 Odd & 1 Even. 2 Odd & 4 Even. These generate 3 Even digits OR 2 Odd & 1 Even digits but the remaining digits are 3 Odd & no Even.
What is the divisible test for the number 6?
6 = 2 x 3So it must satisfy the divisibility tests for both 2 and 3, namely:Any even number for which the sum of its digits is divisible by 3.
What is the smallest digits prime number?
It is 2 which also is the only even prime number
What is your number Clue 1 your number has two digits and there both even Clue 2 the sum of your numbers digit is 10 Clue 3 your number has four as a factor?
Your are 28 or 64
What number has 2 digits the ones digit is odd the tens digit is even the sum of the digits are divisable by 3 the number is a square number?
81
What is the greatest 8 digit even number using prime digits?
To be an even number then the final digit = 2. The largest single prime digit is 7 (as both 8 and 9 are composite). The greatest even number fulfilling the conditions is 77777772.
