81
Single digit primes are 2, 3, 5, 7 Single digit squares are 1, 4, 9 Neither prime nor square are 0, 6, 8 None of that makes a difference if we can't figure out what a "grerate" is. I'll guess you want to know the greatest possible number given those conditions. That would be 985.
1111Improved Answer:-It is 1008 because 1008/9 = 112Any number is divisable by 9 if the sum of its digits equals 9.
Every square of a 4 digit number has more than four digits.
81...........
81
49
Single digit primes are 2, 3, 5, 7 Single digit squares are 1, 4, 9 Neither prime nor square are 0, 6, 8 None of that makes a difference if we can't figure out what a "grerate" is. I'll guess you want to know the greatest possible number given those conditions. That would be 985.
1111Improved Answer:-It is 1008 because 1008/9 = 112Any number is divisable by 9 if the sum of its digits equals 9.
Every square of a 4 digit number has more than four digits.
81...........
81
1
121
81
The number is 81.
The square root of 55 is an irrational number, meaning it never ends and doesn't have a repeating digit pattern, so it has an infinite number of digits.
No, a square number cannot end in just any digit. Specifically, the last digits of square numbers can only be 0, 1, 4, 5, 6, or 9. This is because when you square integers, the resulting last digits are limited to these values based on the last digit of the original number. For example, squaring a number that ends in 2 gives a last digit of 4, while squaring a number that ends in 3 gives a last digit of 9.